Imposible.
only using the numbers once
For example, by adding 1 + 1 + 1 ... (a total of 100 times).
No.
No. Not if the numbers are to be used only once. There is only one 5 (or a multiple of 5) in the numbers available. Using times and divide cannot produce any more of them. On the other hand 100 is divisible by 5*5 so at least two fives are required. If the numbers can be used more than once then 2*2*5*5 is one possible solution.
Imposible.
1+2+3+4+5+6+7+(8x9)=100
only using the numbers once
(100 - 25 - (3 * 6) - 1) * 9
2x4x3 is 24+1 is 25, x4 is 100. 2x3 is 6+4 is 10. 10*100 is 1000. That is one way. All ways require using the numbers more than once
recu
For example, by adding 1 + 1 + 1 ... (a total of 100 times).
We can get 29 by using their squares like: (42 + 32 + 22) / 1 = 29
2*6*7 + 4*5 - 1 - 3 = 84 + 20 - 1 - 3 = 104 - 4 = 100 3*5*7 + 4 - 1 - 2 - 6 = 105 + 4 - 9 = 109 - 9 = 100 4*5*6 - 3*7 + 2 - 1 = 120 - 21 + 2 - 1 = 122 - 22 = 100
No.
4(2+3)-1=19
The answer is 34(1)^2.