The answer will depend on which country's currency the question is about.
77 has four factors: 1, 7, 11, 77.
There are many ways to get 77 using simple arithmetic: 33 + 44 = 77, 1 + 76 = 77, 154/2 = 77, 7 x 11 = 77, etc.
It's hard to represent this with only the characters on the keyboard, so I'll have to explain it as best I can. Using bar notation to denote an infinitely repeating decimal, 0.4444444... can be represented as .4 with a bar over the 4. The best I can do here is to put a line through the four: .4 If you were writing it by hand, the line would be on top of the four, not through it. Then 4/.4 = 9. The square root of 9 is 3, and 34 = 81. 81 - 4 = 77, so we have: sqrt(4/.4)4 - 4 = 77 Substitute the square root symbol for "sqrt()"
7 x 11 = 77
_ (4/0.4)^sqrt4-4 =77 9 81 =77
The only solution that I have ever seen uses some notation that is not so commonly used, namely a bar over 4 to mean the infinitely repeating decimal .44444... which is 4/9 . So, if x = 4/9 is written with one four, then sqrt(4/x) 4 - 4 uses four fours and equals 77 since 4/x = 4 * 9/4 = 9 and sqrt(9)4 - 4 = 34 - 4 = 81 - 4 = 77.
No. 77 is only evenly divisible by 7 and 11.
It is impossible.
The answer will depend on which country's currency the question is about.
Four. The factors of 77 are: 1 7 11 77
77 has four factors: 1, 7, 11, 77.
Four: 1, 7, 11, 77.
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There are many ways to get 77 using simple arithmetic: 33 + 44 = 77, 1 + 76 = 77, 154/2 = 77, 7 x 11 = 77, etc.
The editors should shut up if they don't know how. Yes, if only +-*/() is allowed, It would be impossible. If recurring digits is allowed, The answer is: 4! / (.4` * sqrt(.4`)) - 4 While .4' being 0.4444444444...
77 = 66 + 66/6