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What else can I help you with?
How many eighty-fours are in 672?
There are 77 eighty-fours in 672
How do you make 77 with 4 fours?
[√(4/.4*)]^4 - 4 = [√9]^4 - 4 = 3^4 - 4 = 81 - 4 = 77 N.B. the denominator within the square root is meant to be 0.4 recurring, which is written with a dot above the 4 but I am not able to do this. 0.44444...... = 4/9 Also, if you do (4-40)3 - 4
What is 77 in four 4s?
The only solution that I have ever seen uses some notation that is not so commonly used, namely a bar over 4 to mean the infinitely repeating decimal .44444... which is 4/9 . So, if x = 4/9 is written with one four, then sqrt(4/x) 4 - 4 uses four fours and equals 77 since 4/x = 4 * 9/4 = 9 and sqrt(9)4 - 4 = 34 - 4 = 81 - 4 = 77.
How can you arrange four fours to make 33?
A solution to the four fours problem for the number 33 is: 33 = (4-.4)/.4+4!
How do you make 15 with 4 fours?
(4x4) - (4/4)
How many eighty-fours are in 672?
There are 77 eighty-fours in 672
The answer to 77 on the four fours?
23
In the fours fours challenge how do you get 43?
44 - 4/4
How do you make 77 with 4 fours?
[√(4/.4*)]^4 - 4 = [√9]^4 - 4 = 3^4 - 4 = 81 - 4 = 77 N.B. the denominator within the square root is meant to be 0.4 recurring, which is written with a dot above the 4 but I am not able to do this. 0.44444...... = 4/9 Also, if you do (4-40)3 - 4
Using four fours how can you get 77?
The editors should shut up if they don't know how. Yes, if only +-*/() is allowed, It would be impossible. If recurring digits is allowed, The answer is: 4! / (.4` * sqrt(.4`)) - 4 While .4' being 0.4444444444...
How many fours are in 136?
To find out how many fours are in 136, you divide 136 by 4. The calculation is 136 ÷ 4 = 34. Therefore, there are 34 fours in 136.
How can you arrange four fours to make 33?
A solution to the four fours problem for the number 33 is: 33 = (4-.4)/.4+4!
How do get 7using 4 fours?
To get 7 using 4 fours, you can use the following equation: 4 + 4 - (4/4) = 7.
What is 77 in four 4s?
The only solution that I have ever seen uses some notation that is not so commonly used, namely a bar over 4 to mean the infinitely repeating decimal .44444... which is 4/9 . So, if x = 4/9 is written with one four, then sqrt(4/x) 4 - 4 uses four fours and equals 77 since 4/x = 4 * 9/4 = 9 and sqrt(9)4 - 4 = 34 - 4 = 81 - 4 = 77.
How do you make 32 using 4 fours?
You can make 32 using four fours by employing mathematical operations as follows: [ 32 = (4 \times 4) \times (4 - 4) + 4! ] However, a simpler expression is: [ 32 = (4 + 4) \times (4 + 4) ] Here, you add two fours to get 8 and then multiply it by another pair of fours to achieve 32.
How do you get 24 with 4 fours?
4 times 4 + 4 + 4
How do you make 14 with four fours?
I can do it with 3: 4 * 4 + 4 = 1416(base 16) But that's probably not what you are looking for. The closest I can get is with 5 fours: 4 * 4 - (4 + 4) / 4
