To achieve the number 77 with four fours, the solution is as follows:
sqrt(4/.4)4 - 4
Instead of the second four being equal to four tenths, place a dot over the top to indicate it being equal to four ninths.
There are 77 eighty-fours in 672
[√(4/.4*)]^4 - 4 = [√9]^4 - 4 = 3^4 - 4 = 81 - 4 = 77 N.B. the denominator within the square root is meant to be 0.4 recurring, which is written with a dot above the 4 but I am not able to do this. 0.44444...... = 4/9 Also, if you do (4-40)3 - 4
The only solution that I have ever seen uses some notation that is not so commonly used, namely a bar over 4 to mean the infinitely repeating decimal .44444... which is 4/9 . So, if x = 4/9 is written with one four, then sqrt(4/x) 4 - 4 uses four fours and equals 77 since 4/x = 4 * 9/4 = 9 and sqrt(9)4 - 4 = 34 - 4 = 81 - 4 = 77.
A solution to the four fours problem for the number 33 is: 33 = (4-.4)/.4+4!
(4x4) - (4/4)
There are 77 eighty-fours in 672
23
44 - 4/4
[√(4/.4*)]^4 - 4 = [√9]^4 - 4 = 3^4 - 4 = 81 - 4 = 77 N.B. the denominator within the square root is meant to be 0.4 recurring, which is written with a dot above the 4 but I am not able to do this. 0.44444...... = 4/9 Also, if you do (4-40)3 - 4
The editors should shut up if they don't know how. Yes, if only +-*/() is allowed, It would be impossible. If recurring digits is allowed, The answer is: 4! / (.4` * sqrt(.4`)) - 4 While .4' being 0.4444444444...
The only solution that I have ever seen uses some notation that is not so commonly used, namely a bar over 4 to mean the infinitely repeating decimal .44444... which is 4/9 . So, if x = 4/9 is written with one four, then sqrt(4/x) 4 - 4 uses four fours and equals 77 since 4/x = 4 * 9/4 = 9 and sqrt(9)4 - 4 = 34 - 4 = 81 - 4 = 77.
A solution to the four fours problem for the number 33 is: 33 = (4-.4)/.4+4!
To get 7 using 4 fours, you can use the following equation: 4 + 4 - (4/4) = 7.
Oh, dude, you wanna play with numbers? Okay, so like, to get 20 with 4 fours, you can do 4 + 4 + 4 + 4 + 4 = 20. Or you could be all fancy and do 4! + 4 - 4/4 = 20. Math can be fun, right?
4 times 4 + 4 + 4
I can do it with 3: 4 * 4 + 4 = 1416(base 16) But that's probably not what you are looking for. The closest I can get is with 5 fours: 4 * 4 - (4 + 4) / 4
To get 44 using 4 fours, you can use the following mathematical expression: (4! + 4) + (4/4) = 44. In this equation, the factorial symbol (!) represents the product of all positive integers up to that number. So, 4! = 4 x 3 x 2 x 1 = 24. Adding 4 to 24 gives you 28. Dividing 4 by 4 equals 1. Adding 28 and 1 together equals 29. Finally, 29 + 15 = 44.