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To achieve the number 77 with four fours, the solution is as follows:

sqrt(4/.4)4 - 4

Instead of the second four being equal to four tenths, place a dot over the top to indicate it being equal to four ninths.

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15y ago

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How do you make 77 with 4 fours?

[√(4/.4*)]^4 - 4 = [√9]^4 - 4 = 3^4 - 4 = 81 - 4 = 77 N.B. the denominator within the square root is meant to be 0.4 recurring, which is written with a dot above the 4 but I am not able to do this. 0.44444...... = 4/9 Also, if you do (4-40)3 - 4


Using four fours how can you get 77?

The editors should shut up if they don't know how. Yes, if only +-*/() is allowed, It would be impossible. If recurring digits is allowed, The answer is: 4! / (.4` * sqrt(.4`)) - 4 While .4' being 0.4444444444...


How many fours are in 136?

To find out how many fours are in 136, you divide 136 by 4. The calculation is 136 ÷ 4 = 34. Therefore, there are 34 fours in 136.


What is 77 in four 4s?

The only solution that I have ever seen uses some notation that is not so commonly used, namely a bar over 4 to mean the infinitely repeating decimal .44444... which is 4/9 . So, if x = 4/9 is written with one four, then sqrt(4/x) 4 - 4 uses four fours and equals 77 since 4/x = 4 * 9/4 = 9 and sqrt(9)4 - 4 = 34 - 4 = 81 - 4 = 77.


How can you arrange four fours to make 33?

A solution to the four fours problem for the number 33 is: 33 = (4-.4)/.4+4!


How do get 7using 4 fours?

To get 7 using 4 fours, you can use the following equation: 4 + 4 - (4/4) = 7.


How do you make 32 using 4 fours?

You can make 32 using four fours by employing mathematical operations as follows: [ 32 = (4 \times 4) \times (4 - 4) + 4! ] However, a simpler expression is: [ 32 = (4 + 4) \times (4 + 4) ] Here, you add two fours to get 8 and then multiply it by another pair of fours to achieve 32.


How many fours are in 88?

To find out how many fours are in 88, you divide 88 by 4. Performing the calculation, 88 ÷ 4 equals 22. Therefore, there are 22 fours in 88.


How do you get 24 with 4 fours?

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