By writing in C code the mathematical methods for finding the mean, median and mode of your data taking into account how your data is stored (eg an array; two separate arrays one with data and the other with frequencies; a two dimensional array containing both data and frequencies; an array of structures containing the data instead of arrays; a linked list of structures; etc).
try this---> http://c-pgms.blogspot.com/2008/08/program-to-find-meanmedianand-mode_22.html
Before I start, you didn't put the range, so I can't completely find the answer. If you can give me the range, I can edit this to make it 100% correct The Median is the "Middle number", so we know that the middle number is 5 ab5cd The mode is the number that is repeated most often, and since it is 3, we know that there has to be two 3s, in order to have more 3s than 5s. (We can't have more or else 5 would be the median) 335cd the mode is the average of all of the numbers (3+3+5+c+d)/5=6 now we just need to do simple math to find C and D 11+c+d=30 C+D=19 The Range is the biggest number minus the smallest number (D-3) If you know the range, you can calculate D, and then find C using C+D=19
#include<stdio.h> #define MAXVAL 1000 void sort1(int a[],int n); void median(int a[],int n); void mode(int a[],int n); int main() { int n; int arr[MAXVAL]; int i; printf("Enter the number of elements:"); scanf("%d",&n); printf("Enter the values:"); for(i=0;i<n;i++) { printf("a[%d]=",i); scanf("%d",&arr[i]); } sort1(arr,n); median(arr,n); mode(arr,n); } void sort1(int a[],int n) { int i; int j; int temp; for(i=0;i<n;i++) { for(j=i;j<n;j++) { if(a[i]>a[j]) { temp=a[i]; a[i]=a[j]; a[j]=temp; } } } } void median(int a[],int n) { int median; int mid; if((n%2)==0) { mid=n/2; median=(a[mid-1]+a[mid])/2; } else { mid=(n+1)/2; median=a[mid-1]; } printf("The median is:%d\n",median); } void mode(int a[],int n) { int i; int count1[MAXVAL]; for(i=0;i<n;i++) { count1[i]=0; } for(i=0;i<n;i++) { count1[a[i]]++; } i--; int mode=count1[0]; int j; int k; int flag=0; for(j=0;j<=a[i];j++) { if(count1[j]>count1[mode]) mode=j; } for(j=0;j<=a[i];j++) { for(k=j+1;k<=a[i];k++) { if(count1[j]=count1[k] && count1[j]>count1[mode]) { flag=1; } } } if(flag==1) { printf("Mode cannot be calculated"); } else printf("the Mode is:%d",mode); }
Just as you would do it manually, I mean there is no predefined 'solve_equation' function in C.
Here, i write some formulas of un-group data of Mean, Median, Mode:1. Mean:Σfx/N here N stand for Number to add them.2. MedianL+H/F (n/2 -c) now here i write small "n" that's mean you don't have to add them just count, how much numbers are there in "n" row.3. Mode:Most repeated number is mode answer.
The median.
The mode
The median and mode of any number is the same number. The mode of 5 is 5, as is the median of 5. In other words, you need two or more numbers to determine the median and mode of those numbers.
try this---> http://c-pgms.blogspot.com/2008/08/program-to-find-meanmedianand-mode_22.html
C is a programming language.
In programming, specifically in C and C++, the hashtag (#) is used to include files into the main program and to create macros.
What do you mean by searching in data structure in C.?
The mean is the sum of the sample, divided by the number of samples. The median is the middle number. Good example of this is your grades. You have a d,c,a,b, c,c. Each grade has a number a d is equal to 1 point, c= 2 points, a= 4 points, and a b=3 points. You add these up and divide by the number 7. To find the median write them in order A,b,ccc,d= the median is a C.
Hundred Carbon A vitamin A programming language ...
What exactly do you mean by colors?
Consult with your caregiver. Every model of cpap has different key combinations to get into the programming mode.
It has nothing to do with C, it simply means: add 1 to a variable.