If you mean: 2x+4y = 4 then the graph joins the points: (2, 0) and (0, 1)
-2x plus 3y equals 1
-2x+3y=1 3y=1+2x y=(1+2x)/3 Then proceed to find points by plugging in given or arbitrary values of x.
2x + 6y = 6Subtract 2x from each side:6y = -2x + 6Divide each side by 6:y = -1/3 x + 1The graph is a straight line, with a slope of [ -1/3 ], and intersecting the y-axis at the point [ y = 1 ].
That's not an equation. It doesn't have a graph or an intercept.
If you mean: 2x+4y = 4 then the graph joins the points: (2, 0) and (0, 1)
3
-2x plus 3y equals 1
-2x=2y+5 +2x -2y -2y=2x+5 /-2 y=-1/1+2.5
-2x+3y=1 3y=1+2x y=(1+2x)/3 Then proceed to find points by plugging in given or arbitrary values of x.
Any line which has a gradient which is not 2 will not be parallel to the line y = 2x + 1.
2x + 6y = 6Subtract 2x from each side:6y = -2x + 6Divide each side by 6:y = -1/3 x + 1The graph is a straight line, with a slope of [ -1/3 ], and intersecting the y-axis at the point [ y = 1 ].
the equation should be y =-4/2x+1 that is a way to make it easier to graph
1
y = x2 + 2x + 1zeros are:0 = x2 + 2x + 10 = (x + 1)(x + 1)0 = (x + 1)2x = -1So that the graph of the function y = x + 2x + 1 touches the x-axis at x = -1.
That's not an equation. It doesn't have a graph or an intercept.
As stated these are not lines, but just a collection of algebraic terms. If we change them to y=2x and y=2x-1, then on a graph of y versus x, these are parallel lines separated by vertical distance of 1.