First graph the equation 3x + 4y = 4. Because the equation only has x and y to the first power, it graph will be a straight line. Therefore, just find two points that lie on the graph and draw the straight line that goes through both of them. When x = 0, y is clearly 1, and when y = 0, x = 4/3.
So draw the straight line that goes through (0,1) and (4/3,0), but because the equation does not include the phrase "or equal to," make the line dotted. That indicates that points on the line are not included in the solution set.
Then shade the side of the line that includes all possible solutions. Which side is it? Well, plug in any point, say (0,0), and see if the equation makes sense.
3(0)+4(0) > 4
0 > 4
This is untrue, so shade in the other side of the line, the side that doesn't include the origin. Any (x,y) coordinate on that side of the line will satisfy your inequality.
x < -26.
5x + 4
3x + y = -1 y = -3x - 1 The graph is a straight line, with a slope of -3, passing through the point Y = -1 on the y-axis.
The lines are parallel.
3x+5<x+11 3x<6 x<2
(3x+2)-(5+7x) = 3x+2-5-7x = -4x-3 3x+2 is -4x-3 times greater than 5+7x.
x < -26.
5x + 4
You're asking for the difference: (3x + 2) - (5 - 7x).(3x + 2) - (5 - 7x) =3x + 2 - 5 + 7x =10x - 3.It is (10x - 3) greater.
4
It's a number that is exactly 3 greater than whatever the value of 'x' is at that moment.
3x + y = -1 y = -3x - 1 The graph is a straight line, with a slope of -3, passing through the point Y = -1 on the y-axis.
First of all, if 'x' is 3, then 'x' doesn't equal -3x+3 . You must mean y = -3x + 3.If x=3, then (-3x + 3) = -6 .The graph is the point (3, -6) .
The lines are parallel.
3x + y = c where c is any constant number of your choice.
3x+5<x+11 3x<6 x<2
3x + 2y = 13Subtract 3x from each side:2y = -3x + 13Divide each side by 2:y = (-3/2)x + (13/2)The graph is a straight line, with a slope of (-3/2),through the point (0, 13/2) .