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Start at the origin (0, 0) plot a mark there, then move down 3 and to the right 1 (1, -3) plot a mark there, move down 3 and to the right 1 again (2, -6) and plot a mark there then with a ruler make a line threw the three marks and its graphed!

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Q: How do you graph the equation y -x 3?
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Related questions

What is yx-3 graph equation?

y=x^3


How do you graph the equation y-x 3?

To graph the equation y-x=3, first rearrange it in slope-intercept form by isolating y: y=x+3. This equation represents a line with a slope of 1 and y-intercept of 3. You can plot the y-intercept at (0,3) then use the slope to find another point and draw a straight line connecting the two points.


What line in the graph is it if the equation is y equals x plus 3?

y = x + 3The graph of that equation is a straight line with a slope of 1 (45° rising to the right)and passing through the point y=3 on the y-axis.


Y 2x plus 3 graph?

You can do the equation Y 2x plus 3 on a graph. On this graph the Y would equal 5 and X would equal to 0.


How do you graph the equation y equals x - 3?

y = x - 3The graph is a straight line, passing through the point [ y = -3 ] on the y-axis,and having a slope of [ 1 ].


What is y-intercept of the graph of -305y?

Assuming the graph is: x = - 305 y, then the y intercept is at y = 0Assuming the graph is: x - 3 = 5y, then the y intercept is at y = -3/5The main point for you to realize here is that a graph represents an equation,and " -305y " is not an equation. So some kind of assumption has to be madein order to come up with something that can be graphed.


Solve and graph y equals 3 plus x?

The given equation y=3+x is a linear line with the slope of 1 and y-intercept of 3.


Graph the equation x equals -3?

The is a straight line parallel to the y-axis with an x intercept at -3.


Graph the equation x plus y 3?

Put a dot on the x axis at x=3 and a dot on the y axis at y=3 and draw a straight line between them.


Can you show me how to graph y -x2 - 4x - 3?

y = -x2 - 4x - 3. The constant, 3, tells us where the graph would hit the y-axis. In this case, it would hit the y-axis at -3. Solving the equation y = -(x2 + 4x + 3) ; y=-(x+3)(x+1) Therefore hits the x-axis at -3 and -1. Since it's a parabola (x2), the graph can either start from the top, or from the bottom. An equation starting with ax2 will start from the top, and an equation with -ax2 will start from the bottom. So therefore, the graph starts from the bottom of the page, goes from -3 and -1 on the x-axis and intercepts the y-axis at -3.


When you shift the graph of an equation up or down does every instance of x in the equation change?

Yes, for example if you have y=x but you shifted the equation up 3 units hence: y=x+3. than you will receive a different y from every instance (point) of x. Reference: collegemathhelper.com/2015/11/horizontal-graph-transformations-for.html


What does y-x-2 look like on a graph?

You could not graph (y-x-2) because it has no equal sign in it. In order to graph an equation, there must be a value that the numbers and variables are equal to. (e.g. y=2x+3)