Start at the origin (0, 0) plot a mark there, then move down 3 and to the right 1 (1, -3) plot a mark there, move down 3 and to the right 1 again (2, -6) and plot a mark there then with a ruler make a line threw the three marks and its graphed!
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y=x^3
y = x + 3The graph of that equation is a straight line with a slope of 1 (45° rising to the right)and passing through the point y=3 on the y-axis.
y = x - 3The graph is a straight line, passing through the point [ y = -3 ] on the y-axis,and having a slope of [ 1 ].
The is a straight line parallel to the y-axis with an x intercept at -3.
y = -x2 - 4x - 3. The constant, 3, tells us where the graph would hit the y-axis. In this case, it would hit the y-axis at -3. Solving the equation y = -(x2 + 4x + 3) ; y=-(x+3)(x+1) Therefore hits the x-axis at -3 and -1. Since it's a parabola (x2), the graph can either start from the top, or from the bottom. An equation starting with ax2 will start from the top, and an equation with -ax2 will start from the bottom. So therefore, the graph starts from the bottom of the page, goes from -3 and -1 on the x-axis and intercepts the y-axis at -3.