To plot y = 2x/3, mark the origin, O, on the Cartesian plane.
Think of any multiple of 3. Call this value a. Calculate 2*a/3 and call this value b. Let P be the point (a, b).
Join OP and extend in both directions.
Incidentally, a need not be a multiple of 3, but the calculations are simpler if it is.
Y=X^2 is a function for it forms a parabola on a graph.
-2
Yes, that is a shifted tanX graph, just as you would shift any graft.
3
For a 2-dimensional graph if there is any value of x for which there are more than one values of the graph, then it is not a function. Equivalently, any vertical line can intersect the a function at most once.
Y=X^2 is a function for it forms a parabola on a graph.
y = 5x + 2
What is the area bounded by the graph of the function f(x)=1-e^-x over the interval [-1, 2]?
It would be less steep
You may mean, what is the graph of the function y = x^2 + 3. This graph shows a upward parabola with a y-intercept of 3 and a minimum at x=0.
-2
Any graph with the slope of -1/2
y equals x-4 plus 2 is the same as y = x-2. You just translate the graph of y=x, 2 units to the right, OR 2 down.
The graphs of y = 5x - 2 and y = x - 2 will have different slopes but with the same y intercepts.
Yes. The graph of [ x = 2 ] is a vertical line.
Given the function g(f(x)) = 2-x, you can find the domain as you would with any other function (i.e. it doesn't matter if it's composite). The output, however, has to be a real number. With this function, the domain is all real numbers. If you graph it, you see that the function is defined across the entire graph, wherever you choose to plot it.
Yes, that is a shifted tanX graph, just as you would shift any graft.