Well, the best way I think is to form a table with X and Y values. For example:
When X = 0 Y = 0 because Y = 0/10 (plug 0 for X)
When X = 5 Y = 5/10 or 1/2 etc...
Do this for both positive and negative number and plot your X and Y values...it's a linear equation so it'll be a line that goes through (0,0). Using the above examples, you should have a plot point at (0,0) and (5, .5)
The answer to that is a graph, which I cannot show you (it's not possible on this text box). I will tell you the function form of the problem: y= -10/8x + 1/4
To work out y=-5x-10 you can plot a graph.
-5
7/10 - 3/10 = 4/10
You will need to plot your first point on the y-intercept which in this equation is -10. From there you will need to use the slope, which in this equation is "x" to tell you to rise 1 and move over 1. You will find the graphed line below.
Yes, because you can rewrite it as: y = -x/10 Which is a line. When you graph the above equation, the graph passes the vertical line test - meaning that the graph never intersects with any vertical line more than once.
The answer to that is a graph, which I cannot show you (it's not possible on this text box). I will tell you the function form of the problem: y= -10/8x + 1/4
To work out y=-5x-10 you can plot a graph.
-5
9/10 divided by 10/9 equals 9/10 x 9/10 equals 81 /100
0.1 (10%)
7/10 - 3/10 = 4/10
9/10 = 0.9 or 0.90
No, 4/5 equals 0.8 while 7/10 equals 0.7
the answer is 9 over 10 cause 54 divided by 6 equals 9 and 60 divided by 6 equals 10 so its 9 over 10
5x - 10 = 20Add 10 to each side:5x = 30Divide each side by 5:x = 6If you feel that you must graph this equation for some reason,then your graph is a vertical line, parallel to the y-axis, passingthrough the point [ x=6 ] on the x-axis.
You will need to plot your first point on the y-intercept which in this equation is -10. From there you will need to use the slope, which in this equation is "x" to tell you to rise 1 and move over 1. You will find the graphed line below.