This graph looks very similar to the famous equation of y equal 1 over x; in either case you get a curve which asymtotically approaches infinity at the y axis where x=0, and which asymptotically approaches zero as x approaches infinity. The difference is that if it is 3 over x, all the values will be three times higher than if it is 1 over x. But the shape of the curve is the same.
In statistics, a graph and a chart are the same. In arithmetic, a graph is the plot of a function over values. There are no charts.
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If you can differentiate the function, then you can tell that the graph is concave down if the second derivative is negative over the range examined. As an example: for f(x) = -x2, f'(x) = -2x and f"(x) = -2 < 0, so the function will be everywhere concave down.
bend over and ill show you
No, flipping a function is not the same as moving a function. Flipping a function typically refers to reflecting it over an axis, such as the x-axis or y-axis, which changes its orientation but not its position on the graph. Moving a function, on the other hand, involves translating it vertically or horizontally without altering its shape. Each operation affects the function's graph differently.
What is the area bounded by the graph of the function f(x)=1-e^-x over the interval [-1, 2]?
Because the inverse of a function is what happens when you replace x with y and y with x.
When a function is multiplied by -1 its graph is reflected in the x-axis.
Yes. 0.3 with a bar over it is 1/3, which is a rational number.
In statistics, a graph and a chart are the same. In arithmetic, a graph is the plot of a function over values. There are no charts.
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an exponential function flipped over the line y=x
To find the area under a graph, you can use calculus by integrating the function that represents the graph. This involves finding the definite integral of the function over the desired interval. The result of the integration will give you the area under the graph.
Yes, it does.
x
Multiply by -1
y=x