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2y + 10 = x can be written as y = x/2 - 5. This defines a straight line graph with a slope of 1/2 and a y intercept of -5.
To find the y-intercept of 2y - 5x = 14, we can set x = 0 and solve for y.2y - 5(0) = 142y = 14y = 7So the y-intercept occurs at (0, 7).
-x+2y = 6 2y = x+6 y = 1/2x+3 Therefore the slope is 1/2 and the y intercept is 3
2x-3y=5 and x-2y=12x-3y+2y=5 and x-2y+2y=12x-y=5 and x=12(1)-y=52-y=52-y-2=5-2-y=3y=-3(x,y) is (1,-3)
2y = x + 4Divide each side by 2:y = (1/2)x + 2The graph is a straight line with a slope of (1/2) and a y-intercept of 2.