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To graph the equation (x - 2y = 5), first, rearrange it into slope-intercept form (y = mx + b). This gives (2y = x - 5) or (y = \frac{1}{2}x - \frac{5}{2}). The slope is (\frac{1}{2}) and the y-intercept is (-\frac{5}{2}) (or -2.5). Plot the y-intercept on the graph, then use the slope to find another point, and draw a straight line through these points.
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What is the equation 2y plus 10 equals Xdefines?
2y + 10 = x can be written as y = x/2 - 5. This defines a straight line graph with a slope of 1/2 and a y intercept of -5.
What is the correct answer for 7x plus 2y equals 5?
The equation (7x + 2y = 5) represents a linear relationship between (x) and (y). To express (y) in terms of (x), you can rearrange it to (2y = 5 - 7x), which simplifies to (y = \frac{5 - 7x}{2}). There is no single "correct answer" without specific values for (x) or (y); instead, it describes a line on a graph with infinitely many solutions.
What is the y-intercept of the graph of 2y-5x equals 14?
To find the y-intercept of 2y - 5x = 14, we can set x = 0 and solve for y.2y - 5(0) = 142y = 14y = 7So the y-intercept occurs at (0, 7).
What is the slope and y-intercept of the graph of -x plus 2y equals 6?
-x+2y = 6 2y = x+6 y = 1/2x+3 Therefore the slope is 1/2 and the y intercept is 3
What is the locus of points that satisfies both equations 2x-3y equals 5 and x-2y equals 1?
2x-3y=5 and x-2y=12x-3y+2y=5 and x-2y+2y=12x-y=5 and x=12(1)-y=52-y=52-y-2=5-2-y=3y=-3(x,y) is (1,-3)
Which point is on the graph of 5x-2y equals 4?
When y=4, x=8/5
What is the equation 2y plus 10 equals Xdefines?
2y + 10 = x can be written as y = x/2 - 5. This defines a straight line graph with a slope of 1/2 and a y intercept of -5.
How would you graph the problem x plus 2y or equal to 5?
to graph something you must put it in slope-intercept form y=mx+b so it would be 2y=-x+5 but you must get the y alone so the final answer must be y=-1/2x+2.5. 2.5 is the y intercept and 5 is the slope
Graph the line 5x-10 equals 2y?
2y = 5x - 10Putting into Slope-Intercept form, we have y = 5/2 x - 5. So, the y-intercept is -5 and the slope is 5/2 or 2.5. (x-intercept is 2).
How do you graph the equation x plus 2y equals 4?
First, write out the problem: x+2y=4 then you have to simplify it so that only y is on one side x+2y=4 -4 -4 x+2y-4=0 -2y -2y x-4=-2y / -2 = -1/2x + 2 = y then, draw out a graph: and, let's say, x=4, then you plug that into the equation, and solve for y in this case, if x=4, then y=0, so one of the points would be (4, 0)
What is the correct answer for 7x plus 2y equals 5?
The equation (7x + 2y = 5) represents a linear relationship between (x) and (y). To express (y) in terms of (x), you can rearrange it to (2y = 5 - 7x), which simplifies to (y = \frac{5 - 7x}{2}). There is no single "correct answer" without specific values for (x) or (y); instead, it describes a line on a graph with infinitely many solutions.
What is the y-intercept of the graph of 2y-5x equals 14?
To find the y-intercept of 2y - 5x = 14, we can set x = 0 and solve for y.2y - 5(0) = 142y = 14y = 7So the y-intercept occurs at (0, 7).
What is the slope and y-intercept of the graph of -x plus 2y equals 6?
-x+2y = 6 2y = x+6 y = 1/2x+3 Therefore the slope is 1/2 and the y intercept is 3
What is the locus of points that satisfies both equations 2x-3y equals 5 and x-2y equals 1?
2x-3y=5 and x-2y=12x-3y+2y=5 and x-2y+2y=12x-y=5 and x=12(1)-y=52-y=52-y-2=5-2-y=3y=-3(x,y) is (1,-3)
What is the y-intercept for the graph of the equation 3x - 2y equals 5?
Put in function form. 3X - 2Y = 5 - 2Y = - 3X + 5 Y = 3/2X - 5/2 Y intercept = - 5/2
2Y equals X plus 4 in a graph?
2y = x + 4Divide each side by 2:y = (1/2)x + 2The graph is a straight line with a slope of (1/2) and a y-intercept of 2.
How you do x 2y equals 5 graph?
To graph the equation ( x + 2y = 5 ), first, rearrange it into slope-intercept form (( y = mx + b )). This gives you ( 2y = -x + 5 ) or ( y = -\frac{1}{2}x + \frac{5}{2} ). The y-intercept is ( \frac{5}{2} ) (or 2.5), and the slope is (-\frac{1}{2}), indicating that for every 2 units you move up, you move 1 unit to the right. Plot the y-intercept and use the slope to find another point, then draw a straight line through these points.
