answersLogoWhite

0

The graph of a quadratic function is y = ax + bx + c or y = a(x - h) + k, where (h, k) is the vertex.

Since x2 - 12x + 40 cannot be factored, then I will complete the square which will give me the vertex. So I will draw the parabola (which opens upward) by using the vertex and the y-intercept, (0, 40).

y = x2 - 12x + 40 add and subtract 62

y = x2 - 12x + 62 - 36 + 40

y = (x - 6)2 + 4 so the vertex is (6, 4) which shows that the parabola does not intersect the x-axis.

Since the axis of symmetry is x = 6, and the y-intercept point is (0, 40), I have another point (12, 40). I can also find other points by letting x to be 2, or 3, or 4 and finding the corresponding y-values. For example, if x = 3, then y = 13. So the point (3, 13) will give me its symmetric point (9, 13), and so on. Thus, I can use all these points to draw the parabola.

User Avatar

Wiki User

12y ago

Still curious? Ask our experts.

Chat with our AI personalities

DevinDevin
I've poured enough drinks to know that people don't always want advice—they just want to talk.
Chat with Devin
BlakeBlake
As your older brother, I've been where you are—maybe not exactly, but close enough.
Chat with Blake
BeauBeau
You're doing better than you think!
Chat with Beau

Add your answer:

Earn +20 pts
Q: How do you graph x2-12x 40?
Write your answer...
Submit
Still have questions?
magnify glass
imp