3
Yes, x = -3 would represent a vertical line at abscissa -3, parallel to the y-axis.
The is a straight line parallel to the y-axis with an x intercept at -3.
a constant y=x-3 dy/dx=0 a straight line
-1
First, reflect the graph of y = x² in the x-axis (line y = 0) to obtain the graph of y = -x²; then second, shift it 3 units up to obtain the graph of y = -x² + 3.
3
First of all, if 'x' is 3, then 'x' doesn't equal -3x+3 . You must mean y = -3x + 3.If x=3, then (-3x + 3) = -6 .The graph is the point (3, -6) .
Yes, x = -3 would represent a vertical line at abscissa -3, parallel to the y-axis.
The is a straight line parallel to the y-axis with an x intercept at -3.
Move 3 over the right side of the equation so the equation would be x = -3. The graph of this would be a verticle line at x= -3
False. X = 3 is a vertical line.
You may mean, what is the graph of the function y = x^2 + 3. This graph shows a upward parabola with a y-intercept of 3 and a minimum at x=0.
a constant y=x-3 dy/dx=0 a straight line
-1
x -3y = 0 -x = -x -3y=-x /-3 = /-3 y=1/3x Then solve y for different values of x, record the data , then graph the x and y position for each value of x. so for if x =1 y = 1/3 so one point on the graph is (1,1/3)
The graph of the equation [ x = -3 ] is a straight vertical line, passingthrough the point [ x = -3 ] on the x-axis. Its slope is infinite.