That line is horizontal on the graph. Its slope is zero.
It is a horizontal line 5 units above the x-axis.
The figures are exactly the same, but every point on the first graph is exactly 13 below the corresponding point on the second one.
The equation y = 4x^2 + 5 is a parabola
If: y = -2 and y = 2/5x-4 Then: x = 5 The lines meet at: (5, -2)
y= -5
-5
5
That line is horizontal on the graph. Its slope is zero.
No.
It is a horizontal line 5 units above the x-axis.
17
y - 2 = 5 is the same as y = 7, which is a horizontal line above the x-axis at y=7.
x + y = 5y = -x + 5The graph is a straight line, with [ slope = -1 ], passing through the point [ y = 5 ] on the y-axis.
The figures are exactly the same, but every point on the first graph is exactly 13 below the corresponding point on the second one.
No translation will invert a quadratic graph.
The equation y = 4x^2 + 5 is a parabola