y = log2 x is the inverse of the exponential function f(x) = 2x. It means its graph is a reflection of the graph of f(x) about the line y = x.
Let's find some coordinates for f(x), then reverse them.
We know the graph of an exponential function passes through (0, 1).
(0, 1) to (1, 0)
(1, 21) to (2, 1)
(-1, 2-1) to (1/2, -1)
(2, 22)] to (4, 2)
(-2, 2-2) to (1/4, -2)
(3, 23) to (8, 3)
Just plot the points and connect them with a smooth curve. Be careful, the y-axis is a vertical asymptote.
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If you mean y = -2x-6 then y intersect the graph at (0, -6)
Flipping the graph of the function ( y = x^2 + 2x - 2 ) vertically involves multiplying the entire function by -1. This results in the new equation ( y = -(x^2 + 2x - 2) ), which can be simplified to ( y = -x^2 - 2x + 2 ). So, yes, the flipped graph can be represented as ( y = -(x^2 + 2x - 2) ).
A slanted line on a graph is simply a line segment formed by a linear equation (ex.- y=2x+4) with a slope(y=2x+4) and a y-intercept(y=2x+4). ~Ares
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2
If you mean y = -2x-6 then y intersect the graph at (0, -6)
You can do the equation Y 2x plus 3 on a graph. On this graph the Y would equal 5 and X would equal to 0.
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Flipping the graph of the function ( y = x^2 + 2x - 2 ) vertically involves multiplying the entire function by -1. This results in the new equation ( y = -(x^2 + 2x - 2) ), which can be simplified to ( y = -x^2 - 2x + 2 ). So, yes, the flipped graph can be represented as ( y = -(x^2 + 2x - 2) ).
A slanted line on a graph is simply a line segment formed by a linear equation (ex.- y=2x+4) with a slope(y=2x+4) and a y-intercept(y=2x+4). ~Ares
12
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y = log 2x → x = 1/2 <base of log>y So: y = log102x → x = 1/210y (common logs) y = loge2x → x = 1/2ey (natural logs)
That line is [ y = 2 cos(2x) ].