y = log2 x is the inverse of the exponential function f(x) = 2x. It means its graph is a reflection of the graph of f(x) about the line y = x.
Let's find some coordinates for f(x), then reverse them.
We know the graph of an exponential function passes through (0, 1).
(0, 1) to (1, 0)
(1, 21) to (2, 1)
(-1, 2-1) to (1/2, -1)
(2, 22)] to (4, 2)
(-2, 2-2) to (1/4, -2)
(3, 23) to (8, 3)
Just plot the points and connect them with a smooth curve. Be careful, the y-axis is a vertical asymptote.
-2
If you mean y = -2x-6 then y intersect the graph at (0, -6)
A slanted line on a graph is simply a line segment formed by a linear equation (ex.- y=2x+4) with a slope(y=2x+4) and a y-intercept(y=2x+4). ~Ares
12
y = log 2x → x = 1/2 <base of log>y So: y = log102x → x = 1/210y (common logs) y = loge2x → x = 1/2ey (natural logs)
-2
2
If you mean y = -2x-6 then y intersect the graph at (0, -6)
You can do the equation Y 2x plus 3 on a graph. On this graph the Y would equal 5 and X would equal to 0.
8
3
A slanted line on a graph is simply a line segment formed by a linear equation (ex.- y=2x+4) with a slope(y=2x+4) and a y-intercept(y=2x+4). ~Ares
12
y = log 2x → x = 1/2 <base of log>y So: y = log102x → x = 1/210y (common logs) y = loge2x → x = 1/2ey (natural logs)
-2
-12
That line is [ y = 2 cos(2x) ].