44 / 4 + root(4) is one solution. You can find additional solutions in the Wikipedia article "Four fours".
Only if you subtract three.
There are four 4's in a standard deck of cards.
11 = 4/.4 +4/4 13 =( 4! radical( 4) + 4 )/4 13 = 4/,4/ + radical(4) + radical(4)
1x36, 2x13, 4x9, 20+13. That's a few of them.
44 / 4 + root(4) is one solution. You can find additional solutions in the Wikipedia article "Four fours".
13
Only if you subtract three.
There are four 4's in a standard deck of cards.
4x + 2 = 54
There are 13 cards in each suit of a standard deck of playing cards. The United States flag has 13 stripes representing the original 13 colonies. A baker's dozen consists of 13 items instead of the usual 12.
(33 + 3!) / 3 = (33 + 6) / 3 = 39 / 3 = 13.
Three fours and one half of 4 Or if you mean using only fours and operation signs you develop methods like this: 42 - 4 + (4/4) = 13. In words, four squared (16) take 4 (12), + the sum of 4/4, which is one (13). Obviously, being an prime number, 13 doesn't fit equally into four, so use a combination of different mathematical symbols to change four into many other numbers: 42 = 16 Square Root of four = 2 4! (four factorial) = 24 43 = 64 4/4 = 1 4 + 4 = 8 Combinations of these can be used to make the 13 you're after.
11 = 4/.4 +4/4 13 =( 4! radical( 4) + 4 )/4 13 = 4/,4/ + radical(4) + radical(4)
(.5x5)x5+.5=13
1x36, 2x13, 4x9, 20+13. That's a few of them.
(22/2) + 2 = 11 + 2 = 13