(33 + 3!) / 3
= (33 + 6) / 3 = 39 / 3 = 13.
4=4(3s) 4=12s s= 1/3
3 * 3 / ( 3 * 3 ) = 1 but that uses only four 3s, so 33 / ( 3 * 3 * 3 ) = 1 uses five 3s
You can't unless something is missing in your question.
Use two of the 3s to make 33. Then: 33 - 3 = 11 11 + 3 = 14
3x7+4x2
33/3 = 11
(3 + 3) / .3
Is done by (3/3) plus (3/3) = 2
(3*3+3)/3=4
It could be done by: (3*3)/(3*3) = 1
It could be: 33-(3+3) = 21
PH4 has sp3 hybridization. This means that the phosphorus atom forms four sigma bonds using one 3s orbital and three 3p orbitals.