4=4(3s) 4=12s s= 1/3
3s + 1
There are three thirds (1/3s) in every whole, so there are six thirds in two wholes.
Using 1, 2, and 3, you can make 27 whole numbers.
5 of them with a remainder of 1
3 * 3 / ( 3 * 3 ) = 1 but that uses only four 3s, so 33 / ( 3 * 3 * 3 ) = 1 uses five 3s
It could be done by: (3*3)/(3*3) = 1
4=4(3s) 4=12s s= 1/3
3s + 1
There are three thirds (1/3s) in every whole, so there are six thirds in two wholes.
(1 + 1 + 1)! = 6
-7 = 3s - 1 +1 +1 (add 1 to both sides to get the variable alone) ___ ____ -6 = 3s __ ___ (-6 and 3s both divided by 3) 3 3 -2 = s
Aluminum can make three bonds without hybridization because it has three valence electrons in its 3s and 3p orbitals. Its electron configuration is 1s2 2s2 2p6 3s2 3p1.
no because 2/3s is 2/3s of 1 therefore 1 is more then anything of it
4y - 4 + 3s + 7 - 6a - 4 = 0 4y + 3s + 7 - 6a - 4 = 4 4y + 3s - 6a - 4 = 4 -7 4y + 3s -6a = 4 - 7 + 4 4y + 3s - 6a = -3 + 4 4y + 3s - 6a = 1 y + 3s - 6a = 1/4 y = -3s + 6a + 1/4 3s = -y + 6a + 1/4 s = -1/3y + 6a + 1/4 -6a = -1/3y + a + 1/4 -a = -1/3y x 1/6 + a + 1/4 x 1/6 a = 1/18y - 1 - 1/24 a = 1/18y - 25/24
9+3-1
Using 1, 2, and 3, you can make 27 whole numbers.