Is done by (3/3) plus (3/3) = 2
There are four 3s in 12. This can be determined by dividing 12 by 3, which equals 4. Each division represents one occurrence of the number 3 within 12.
3 + 3 + 3/3 = 7
3 plus 3 plus 3 over 3So 3 + 3 =6. 3 over 3 is 1. 6 + 1 = 7
(3 + 3) / .3
3 * 3 / ( 3 * 3 ) = 1 but that uses only four 3s, so 33 / ( 3 * 3 * 3 ) = 1 uses five 3s
Is done by (3/3) plus (3/3) = 2
You can't unless something is missing in your question.
Use two of the 3s to make 33. Then: 33 - 3 = 11 11 + 3 = 14
It could be: 33-(3+3) = 21
3/3 + 3/3 = 6/3 = 2
33 + (3/3)
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3x7+4x2
3 + 3 + 3/3 = 7
(3+3) / .3