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Pharmacist mixed a 20 percent solution with a 30 percent solution to obtain 100 liters of a 24 percent solution How much of the 20 percent solution did the pharmacist use in the mixture?
10
A 280 mL solution is 20 percent salt How much water should be added to make the solution 14 percent salt?
98 mL
How much salt must be added to 60kg of a 20 percent solution of salt to increase it to 40 percent solution of salt?
20%
How many ounces of 20 percent saline solution must be added to 40 ounces of a 5 percent saline solution to make a 10 percent saline solution?
NOT: 15 ounces to make 10%Correct answer:Twenty ouncesCalculus:Let it be M ounces. Then:20%*(M ounce) + 5%*(40 ounce) = 10%*(M+40 ounce)20*M + 200 = 10*M + 400(20-10)*M = 400-20010M = 200M = 20
How many gallons of a 9 percent salt solution must be mixed with 25 gallons of a 31 percent solution to obtain a 20 percent solution?
25 gallons
How much bleach in 20 gallon water to make 1 percent solution?
A one percent solution means 1 part beach and 99 parts water. So we can answer the question by solving the equation 1 part bleach/99 parts water=x gallons bleach/20 gallons water. You can cross multiply. This is the same as 99x=20 so x=20/99 or .20 Let's check .20 gallons bleach/ 20 gallons water=.01 which is 1% .2 gallons is the same as 3.2 cups or 25.6 fluid oz.
How do you make 10 percent solution from 20 percent solution?
To make a 10% solution from a 20% solution, you can mix equal volumes of the 20% solution with water. For example, to make 1 liter of 10% solution, mix 500 ml of the 20% solution with 500 ml of water.
A pharmacist mixed a 20 percent solution with a 30 percent solution to obtain 100 liters of a 24 percent solution How much of the 20 percent solution did the pharmacist use in the mixture?
A pharmacist mixed a 20 percent solution with a 30 percent solution to obtain 100 liters of a 24 percent solution. How much of the 20 percent solution did the pharmacist use in the mixture (in liters).
Pharmacist mixed a 20 percent solution with a 30 percent solution to obtain 100 liters of a 24 percent solution How much of the 20 percent solution did the pharmacist use in the mixture?
10
A 280 mL solution is 20 percent salt How much water should be added to make the solution 14 percent salt?
98 mL
If you have an order for 20 percent dextrose 500 ml you have 1000 ml bag of dextrose 70 percent how much of the dextrose 70 percent do you need to use to make dextrose 20 percent 500 ml?
To make a 20% dextrose solution, you need to dilute the 70% dextrose solution with water. You need to use 178.57 ml of the 70% dextrose and 321.43 ml of water to make 500 ml of 20% dextrose solution.
How do you make a 20 ppm chlorine solution for a 250 gallon spa using liquid household bleach?
To make a 20 ppm chlorine solution for a 250 gallon spa using liquid household bleach, you would need to add approximately 1.8 fluid ounces of 8.25% bleach to the spa water. This calculation assumes that the bleach is added to a freshly filled spa with no existing chlorine in the water. Be sure to test and adjust the chlorine levels accordingly before using the spa.
How do you make 50 percent to 20 percent solution?
To make a 50% solution from a 20% solution, you need to concentrate the solution by evaporating some of the solvent. This will increase the concentration of the solute in the solution, making it 50%. Keep in mind this process should be done carefully, as it can be hazardous.
How many ounces of 20 percent saline solution must be added to 40 ounces of a 5 percent saline solution to make a 10 percent saline solution?
NOT: 15 ounces to make 10%Correct answer:Twenty ouncesCalculus:Let it be M ounces. Then:20%*(M ounce) + 5%*(40 ounce) = 10%*(M+40 ounce)20*M + 200 = 10*M + 400(20-10)*M = 400-20010M = 200M = 20
How much salt must be added to 60kg of a 20 percent solution of salt to increase it to 40 percent solution of salt?
20%
How many gallons of a 12 percent indicator solution must be mixed with a 20 percent indicator solution to get 10 gallons of a 14 percent solution?
Let x represent the amount of 12% solution and (10-x) represent the amount of 20% solution. The equation to solve is: 0.12x + 0.20(10-x) = 0.14(10). Solving for x gives x = 4, so you need 4 gallons of the 12% solution and 6 gallons of the 20% solution to make 10 gallons of the 14% solution.
What quantity x of a 65 percent acid solution must be mixed with a 20 percent solution to produce 300 mL of a 45 percent solution?
133.33
