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How much water must be added to 40 ml of a 25 percent by weight solution to make a 2 percent by weight solution?

About 80ml of water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution.


How much water added to convert a 10 percent solution to 02 percent solution?

add 4 parts water per part solution


How much water should be added to 15 g of salt solution to obtain 15 percent salt solution?

Dissolve 15 g salt in 100 mL water.


How much of a 50 percent solution should be added to 1 liter to make a 25 percent solution?

Mix this 50% solution in equal quantities with water(?) to halve it's strength. So use 1 litre of the 50% solution and 1 litre of water of that's what you are diluting it with.


How much water should be added to 1 gallon of pure antifreeze to obtain a solution that is 60 percent antifreeze?

2 gallons.


How much water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution?

To make a 2% solution from a 25% solution, you need to dilute it. Let x ml be the amount of water needed. Using the equation for mass balance: 0.25(40) = 0.02(40 + x), solve for x to find that x = 875 ml of water needs to be added.


How many ml of water should be added to 95 percent ethyl alcohol to make 1 liter of a 30 percent ethyl alcohol solution?

684 ml


How much water should be added to 1 gallon of pure antifreeze to obtain a solution that is 80 percent antifreeze?

0.25 gallons of water (or 1 quart)


How much water must be added to 12 L of a 40 percent solution of alcohol to obtain a 30 percent solution?

4 litres


How much water should be added to 30 gallons of a solution that is 70 percent antifreeze in order to get a mixture that is 60 percent antifreeze?

First off do not use tap water. Use only distilled water. You will need to add 3 gallons of distilled water to the solution to get 60% antifreeze and 40% distilled water or a 60/40 mix.


How much water must be added to 12 grams of a 90 percent iodine solution to produce a 25 percent iodine solution?

12*(90%)=10.8=X*.25 10.8/.25=X=43.2 43.2-12=31.2 31.2 grams of water must be added


How much water must be added to a gallon of 10 percent saline solution to create a 2 percent solution?

There is 1 gallon of 10% solution...There is 0% saline in water...The equation is (0.1)(1) + 0x = 0.02 (x+1)...Answer is: 4 gallons. Hope I helped!!:)