You can make 26 using the numbers 2, 6, and 7 by performing the operation: ( 6 \times 7 - 2 = 42 - 2 = 40 ). Then, you can further simplify this to ( 6 \times 7 - 6 \times 2 = 42 - 12 = 30 ). However, that doesn't yield 26 directly. Instead, you could use the combination ( 6 \times 7 - 6 ) which equals 36, then subtract 10 to get 26, but that requires additional numbers. A direct method using only those three numbers is not straightforward without additional operations or numbers.
You can use five 2s to make 26 by using the following mathematical expression: ( (2 + 2) \times (2 + 2) + 2 ). This simplifies to ( 4 \times 4 + 2 = 16 + 2 = 18 ), which does not yield 26. Instead, the correct expression would be ( 22 + 2 + 2 ). However, a valid approach is to use ( 22 = 2 \times 10 + 2 ), making it possible to achieve 26 using five 2s.
how do i make 17 using only 2 4 6 8
10- 1 cent 14 - 5 cents 2- 10 cents
The prime factors of 26 are 2 and 13.
4 + 3 + 2 - 1 = 8
22! + (2 x 2/2) = (4 x 3 x 2 x 1) + (2 x 1) = 24 + 2 = 26
8*5 - 7*2 = 40 - 14 = 26
Assuming you are using the standard English alphabet, the number of combinations you can make are: 26 x 26 = 676 combinations.
You can use five 2s to make 26 by using the following mathematical expression: ( (2 + 2) \times (2 + 2) + 2 ). This simplifies to ( 4 \times 4 + 2 = 16 + 2 = 18 ), which does not yield 26. Instead, the correct expression would be ( 22 + 2 + 2 ). However, a valid approach is to use ( 22 = 2 \times 10 + 2 ), making it possible to achieve 26 using five 2s.
how do i make 17 using only 2 4 6 8
No, the closest you can get is 40p using 2 x 20p coins.
no
You can use three 2s to make 26 as follows (2x2)! + 2 = 26 So you can simply make 26 with five 2s as (2x2!) + 2 - 2 + 2 = 26
34+1-2
(5-2)*4 = 12
10- 1 cent 14 - 5 cents 2- 10 cents
Its immposible.