how do i make 17 using only 2 4 6 8
10- 1 cent 14 - 5 cents 2- 10 cents
The prime factors of 26 are 2 and 13.
trunc(79/35) = 2
4 + 3 + 2 - 1 = 8
22! + (2 x 2/2) = (4 x 3 x 2 x 1) + (2 x 1) = 24 + 2 = 26
8*5 - 7*2 = 40 - 14 = 26
Assuming you are using the standard English alphabet, the number of combinations you can make are: 26 x 26 = 676 combinations.
how do i make 17 using only 2 4 6 8
No, the closest you can get is 40p using 2 x 20p coins.
You can use three 2s to make 26 as follows (2x2)! + 2 = 26 So you can simply make 26 with five 2s as (2x2!) + 2 - 2 + 2 = 26
no
10- 1 cent 14 - 5 cents 2- 10 cents
Yes, you can make 11 using only four 2s by using the following mathematical expression: (2 + 2) x (2 + 2) = 4 x 4 = 16. Then, subtract (2/2) to get 16 - 1 = 15. Finally, take the square root of 15 to get √15 ≈ 3.87, which is close to 4. Therefore, using four 2s, you can approximate 11 by following these steps.
34+1-2
(5-2)*4 = 12
Its immposible.