Let's assume you have 1 L of the 37% solution by volume of chemical A. So your solution would contain 0.37 L of A & 0.63 L of water.
0.37 L of A / (0.37 L of A + 0.63 L of water) = 37% solution of A
Obviously in order to dilute the solution to 2% we have to add water. Now we need to figure out how much. We'll call it X. So you set up the ratio as follows & solve for X.
0.37 / (0.37 + 0.36 + X ) = 0.02
0.37 = 0.02 (1.00 + X)
0.37 = 0.02 + 0.02X
0.37 - 0.02 = 0.02 + 0.02X - 0.02
0.35 = 0.02X
0.35/0.02 = X
X = 17.5, so you would have to add 17.5 L of water to the originial 37% solution to dilute it to 2%.
Obviously this answer will change depending on how much of the 37% solution you have to start with but the procedure to figure it out is still the same.
You stare at it
A. 16 of 18 percent and 2 of 9 percent b. 14 of 18 percent and 4 of 9 percent c. 16 of 9 percent and 2 of 18 percent d. 14 of 9 percent and 4 of 18 percent
74 37% of 100 = 37 200 = 2 * 100 (37% of 200) = 2 * (37% of 100) Again, 37% of 100 = 37 37 * 2 = 74
0.37537 1/2%= 37 + (1 ÷ 2)%= 37 %+ 0.5%= 37.5%/100%= 0.375 in decimal
To determine if ( (2, 3) ) is a solution to the equation ( 8x + 7y = 37 + 2y + 4x - 2 ), we first substitute ( x = 2 ) and ( y = 3 ) into the equation. This gives us ( 8(2) + 7(3) = 37 + 2(3) + 4(2) - 2 ). Calculating both sides results in ( 16 + 21 = 37 + 6 + 8 - 2 ), which simplifies to ( 37 = 49 ). Since both sides are not equal, ( (2, 3) ) is not a solution.
About 80ml of water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution.
2%
You stare at it
To make a 2% solution from a 25% solution, you need to dilute it. Let x ml be the amount of water needed. Using the equation for mass balance: 0.25(40) = 0.02(40 + x), solve for x to find that x = 875 ml of water needs to be added.
A. 16 of 18 percent and 2 of 9 percent b. 14 of 18 percent and 4 of 9 percent c. 16 of 9 percent and 2 of 18 percent d. 14 of 9 percent and 4 of 18 percent
A 3 percent solution is 1.5 times as strong as a 2 percent solution.
74 37% of 100 = 37 200 = 2 * 100 (37% of 200) = 2 * (37% of 100) Again, 37% of 100 = 37 37 * 2 = 74
To make a 2% sodium hypochlorite solution from a 12% solution, you can set up the equation: 12% solution * x litres = 2% solution * 100 litres Solving for x, you get: x = (2% solution * 100 litres) / 12% = 16.67 litres Therefore, you would need 16.67 litres of the 12% sodium hypochlorite solution to make 100 litres of a 2% solution.
2 percent bromine solution typically has a reddish-brown color.
It's 74%. The easiest way to convert a fraction to a percent is to make the denominator 100, because then the numerator will be your percent. So to make 37/50 have a denominator of 100, you have to multiply both numbers by 2 (because 50*2 is 100). That gives you a new fraction of 74/100, so 74% is your percentage.
Decant a small measured unit of the acetic acid. (Keep the amount small compared to what you need.) Now consider. If you added an equal amount of water to this (remember acid into water, never the reverse), it would be 1/2 as concentrated, or .44. If you added another equal amount, it would be 1/3 as concentrated as 0.88 concentration or 0.2933.... So we turn to our friend, Mr. Al G. Bra, and ask What "X amount" of water would we have to combine with 88 percent acetic acid to get 2 percent acetic acid? Well it looks like: 0.88/(1+X) = 0.02 ; solve for X: X=43 times the amount decanted. Fill a beaker with 43 units of water. Pour the small amount of acid into the water. Done.
0.37537 1/2%= 37 + (1 ÷ 2)%= 37 %+ 0.5%= 37.5%/100%= 0.375 in decimal