If 2s = 5 then s = 2.5. So by letting s equal 2.5 (two and one half) you will allow 2s to equal 5.
14s 2d 7 - 6s 4d 5 + 8s 2d 3/2s 2d = 14s 7 - 3s 2s 5 + 4s 3
22+22
you do 2 + 2
39
If 2s = 5 then s = 2.5. So by letting s equal 2.5 (two and one half) you will allow 2s to equal 5.
You can use three 2s to make 26 as follows (2x2)! + 2 = 26 So you can simply make 26 with five 2s as (2x2!) + 2 - 2 + 2 = 26
If p = 2s + 5, then s = (p-5)/2 or 1/2 (p-5) --- p = 2s +5 p-5 = 2s (p-5)/2 = s
2r + 2s = 50 2r - s = 17 therefore 4r - 2s = 34 Add so that you can eliminate one of the variables: 2r + 2s = 50 4r - 2s = 34 ---------------- 6r + 0s = 84 Solve for r: 6r = 84 r = 14 Substitute r into one of the original equations: 2(14) + 2s = 50 28 + 2s = 50 2s = 22 s = 11 Doublecheck with the other original equation: 2(14) - 11 = 28 - 11 = 17
2s(-s^3 + 2s^2 - 5) -2s(s^3 - 2s^2 + 5)
2 + 2 + 2 + 2/2 = 6 - 1 = 5
(2+2+2)2 - 2 = 34
2 + 2 * 2(2+2) = 2 + 2 * 24 = 2 + 2 * 16 = 2 + 32 = 34
36
3 and 5
14s 2d 7 - 6s 4d 5 + 8s 2d 3/2s 2d = 14s 7 - 3s 2s 5 + 4s 3
2s2+7s-15 = (2s-3)(s+5) when factored