5 of them with a remainder of 1
4=4(3s) 4=12s s= 1/3
-6r - s
It is 3.833... (3s repeating).
Points: (s, 2s) and (3s, 8s) Slope: (8s-2s)/(3s-s) = 6s/2s = 3 Perpendicular slope: -1/3 Midpoint: (s+3s)/2 and (2s+8s)/2 = (2s, 5s) Equation: y-5s = -1/3(x-2s) => 3y-15s = -1(x-2s) => 3y = -x+17x Perpendicular bisector equation in its general form: x+3y-17s = 0
4s-5-3s =s-5 The s and 5 can not subtract because they aren't like terms. Like terms have the same variable.
s = 15
5 of them with a remainder of 1
A pentagon has 5 sides.A regular pentagon has every side the same length.Perimeter = 5 x 3s= 15 s(whatever unit a s is, other than a second.)
Let F = father's age Let S = son's age F = 3S F - 5 = 4(S-5) F - 5 = 4S -20 F = 4S - 15 F = 3S 3S = 4S-15 S = 15, age of son
5 + 2s + s = 3s - s + 8 Combining like terms on the same side: 5 + 3s = 2s + 8 Subtracting 2s from both sides: 5 + s = 8 Subtracting 5 from both sides: s = 3
135=3s +15 120=3s 40=s
2s + s + 12 =132 ie 3s = 132 -12 3s = 120 s = 40
4=4(3s) 4=12s s= 1/3
5s - 3 = 3s - 92s = -6s = -3
Well, honey, the least common multiple of a monomial like a^3s and s^2 is simply a^3s^2. You just gotta take the highest power of each variable that appears in either monomial, slap 'em together, and there you have it. Math made sassy.
To solve the equation 2s + s + 12 = 132, you first combine like terms on the left side. This gives you 3s + 12 = 132. Next, you isolate the variable by subtracting 12 from both sides to get 3s = 120. Finally, you divide by 3 on both sides to find that s = 40.