To simplify the expression (3s - 5s - 5), combine the like terms (3s) and (-5s). This gives (-2s - 5). Thus, the simplified answer is (-2s - 5).
5 of them with a remainder of 1
To simplify the expression (2s + 3s - s), combine the like terms. First, add (2s) and (3s) to get (5s). Then subtract (s) from (5s), resulting in (4s). Thus, the simplified expression is (4s).
4=4(3s) 4=12s s= 1/3
-6r - s
Argon has a total of 8 electrons, which are distributed in its electron configuration as 1s² 2s² 2p⁶ 3s² 3p⁶. In terms of orbitals, argon has 1s, 2s, 2p, 3s, and 3p orbitals. Specifically, there are 1 s orbital, 1 p orbital for the second energy level, and 1 s and 1 p orbital for the third energy level, giving a total of 5 orbitals (1s, 2s, 2p, 3s, and 3p).
4s-5-3s =s-5 The s and 5 can not subtract because they aren't like terms. Like terms have the same variable.
s = 15
5 of them with a remainder of 1
A pentagon has 5 sides.A regular pentagon has every side the same length.Perimeter = 5 x 3s= 15 s(whatever unit a s is, other than a second.)
Let F = father's age Let S = son's age F = 3S F - 5 = 4(S-5) F - 5 = 4S -20 F = 4S - 15 F = 3S 3S = 4S-15 S = 15, age of son
5 + 2s + s = 3s - s + 8 Combining like terms on the same side: 5 + 3s = 2s + 8 Subtracting 2s from both sides: 5 + s = 8 Subtracting 5 from both sides: s = 3
135=3s +15 120=3s 40=s
To simplify the expression (2s + 3s - s), combine the like terms. First, add (2s) and (3s) to get (5s). Then subtract (s) from (5s), resulting in (4s). Thus, the simplified expression is (4s).
2s + s + 12 =132 ie 3s = 132 -12 3s = 120 s = 40
4=4(3s) 4=12s s= 1/3
5s - 3 = 3s - 92s = -6s = -3
Well, honey, the least common multiple of a monomial like a^3s and s^2 is simply a^3s^2. You just gotta take the highest power of each variable that appears in either monomial, slap 'em together, and there you have it. Math made sassy.