A rectangle is constructed with four sides, one pair each of two lengths. You've
listed nine different lengths in the question. I can't tell what type of monstrosity
you have in mind, but I'm sure that it's no rectangle.
L + W = P/2 = 49 so Length must be greater than 35 cm
To find the perimeter of a rectangle, you add up the lengths of all its sides. In this case, the rectangle has two sides of 14 cm and two sides of 32 cm. Therefore, the perimeter would be 14 + 14 + 32 + 32 = 92 cm. To find the area of a rectangle, you multiply the length by the width. In this case, the length is 32 cm and the width is 14 cm. Therefore, the area would be 32 x 14 = 448 square cm.
Area of square: 10*10 = 100 square m Area of rectangle: 14*10 = 140 square m
Area of rectangle: 3 times 14 = 42 square cmPerimeter of rectangle: 3+14+3+14 = 34 cm
Any shape with such an area will do, for example: Draw a rectangle 1 cm wide and 47 cm long; Draw a rectangle 4.7 cm wide and 10 cm long; Draw an L shape with side lengths (going clockwise from the top) 1 cm, 19 cm, 13 cm, 2 cm, 14 cm, 21 cm.
it is 14
14 tiles
The dimensions of the rectangle will then work out as 14 cm by 10 cm because the perimeter is 14+10+14+10 = 48 cm
for perimeter, just add all the side lengths 16+16+14+14=60 inches
Without further information it is impossible to say (exactly): If the rectangle was 0.5 x 6.5, its perimeter is 14 units and its area is 3.25 units2 If the rectangle was 1 x 6, its perimeter is 14 units and its area is 6 units2 If the rectangle was 2 x 5, its perimeter is 14 units and its area is 10 units2 If the rectangle was 3 x 4, its perimeter is 14 units and its area is 12 units2 If the rectangle was 3.5 x 3.5, its perimeter is 14 units and its area is 12.25 units2 (and it's a square). It all depends upon the lengths of the longer and shorter sides of the rectangle: as long as 2 x longer + 2 x shorter = 14, any area greater than 0 units2 and less than or equal to 12.25 units2 can be made.
the side lengths would be 7, 7, 2 ,2 so... 7*2=14<-- area or 14, 14,1, 1 so...14*1=14<-- area
L + W = P/2 = 49 so Length must be greater than 35 cm
To find the perimeter of a rectangle, you add up the lengths of all its sides. In this case, the rectangle has two sides of 14 cm and two sides of 32 cm. Therefore, the perimeter would be 14 + 14 + 32 + 32 = 92 cm. To find the area of a rectangle, you multiply the length by the width. In this case, the length is 32 cm and the width is 14 cm. Therefore, the area would be 32 x 14 = 448 square cm.
14 lengths of 9 cm is equivalent to 50.8 inches. This is NOT the same as the area of a 14 cm x 9 cm rectangle.
A golden rectangle cannot have both its sides as whole numbers. The ratio of the sides of the rectangle is [1 + sqrt(5)]/2 so if one side is a positive whole number, the other must be an irrational number.
The perimeter of a rectangle can be calculated by adding up the lengths of all its sides. In this case, the rectangle is 7 inches by 8 inches, so its perimeter would be 2(7) + 2(8) = 14 + 16 = 30 inches.
Area of square: 10*10 = 100 square m Area of rectangle: 14*10 = 140 square m