L + W = P/2 = 49 so Length must be greater than 35 cm
P (perimeter of a rectangle) = 2*l+2*w 2*24+2*w > 100 2*w > 52 w > 26 Any width greater than 26cm will cause the perimeter to be greater than 100cm.
The perimeter of a rectangle is 2 x length + 2 x width. If the width is 16 then 78 = 2 x length + 2 x 16 2 x length = 78 - 32 = 46 length = 23. For the perimeter to be greater than 78 cm, the length must be greater than 23 cm
Conventionally, length > width. With that assumption, if L is the length and W the width (both in metres) then 3.75 < L < 7.5 and W = 7.5 - L If L = 3.75 then W = L and the rectangle becomes a square.
For a fixed area, the perimeter is minimum for a circle, but has no maximum. Fractal figures (such as Koch snowflake) may have a finite area within an infinite perimeter.
To maximize the area of a rectangle with a fixed perimeter, the rectangle should be a square. Given 14 inches of string, the perimeter ( P ) is 14, so each side of the square would be ( \frac{14}{4} = 3.5 ) inches. The area ( A ) of the square is then ( A = 3.5 \times 3.5 = 12.25 ) square inches. Thus, the largest rectangular area that can be enclosed is 12.25 square inches.
For a fixed perimeter, the area will always be the same, regardless of how you describe the rectangle.
The greatest area for a fixed perimeter will be when all the sides are equal or when the rectangle approaches the shape of a square.
Any length greater than 9 cm.
P (perimeter of a rectangle) = 2*l+2*w 2*24+2*w > 100 2*w > 52 w > 26 Any width greater than 26cm will cause the perimeter to be greater than 100cm.
nope because if u have a square with a side length of 4 then the perimeter is 16 and the area is 16 and say if u have a rectangle with side lengths of 2 and 6 then the perimeter is 16 but the area is 12 so the answer is no
You dont
The maximum area for a rectangle of fixed perimeter is that of the square that can be formed with the given perimeter. 136/4 = 34, so that the side of such a square will be 34 and its area 342 = 1156.
fixed perimeter is the perimeter being fixed
The perimeter of a rectangle is 2 x length + 2 x width. If the width is 16 then 78 = 2 x length + 2 x 16 2 x length = 78 - 32 = 46 length = 23. For the perimeter to be greater than 78 cm, the length must be greater than 23 cm
Anything greater than 24 cm. P = 2*L + 2*W, since the length is fixed at 24cm we have: 2*(24cm) +2*W > 96cm 2W > 96 - 48cm 2W > 48cm, or Width > 24cm. So any width greater than 24cm will make the perimeter >96cm. Obviously a width of 24cm wouldn't work since a polygon with all four sides equal would be a square and not a rectangle.
A perimeter that will not change.
Recall that the perimeter is: P=2*L+2*W If L=27 cm, find W such that P>86 cm P>86 cm 2*L+2*W>86 cm 54 cm+2*W>86 cm 2*W>32 cm W>16 cm So widths greater than 16 cm will make the perimeter greater than 16 cm.