In any convex polygon with n sides there are n - 2 nonoverlaping triangles, so the interior angle sum is 180(n - 2) degrees. Since an exterior angle of a polygon is formed by extending only one of its sides, then we obtain n straight lines with angle sum of180n degrees. Therefore, 180(n - 2) + the sum of exterior angles = 180n 180n - 360 + the sum of exterior angles = 180n (subtract 180n and add 360 to both sides) the sum of exterior angles = 360 degrees.
360/(180-165)=24the 360 comes from the sum of the exterior angles proof and the 180 comes from the linear pair of exterior angles.
180 Proof: 30-60-90 Triangle 45-45-90 * * * * * The answer is correct, but two examples (or even a million) do not constitute mathematical PROOF.
Mathematical logic.
Here is one way to prove it. It is easier if the decagon is convex but the proof is valid even if not.Take any point P in the plane. Again, it is easier if this point is inside the decagon but the proof is valid even if it is not.Join all the vertices of the decagon to this point. So now you have ten triangles with a common vertex P.The angles of these ten triangles form the internal angles of the decagon plus all the angles around P.So the sum of the internal angles of the decagon is equal to the sum of the internal angles of all ten triangles with P as their common vertex minus the 360 degrees worth of angles at P itself.The sum of the interior angles of each triangle is 180 degrees so the sum of ten triangles with common vertex P is 180*10 = 1800 degrees.So the internal angles of the decagon add to 1800 - 360 = 1440 degrees.
Reflect the line of physics And angles will have the dame degrees either side As taught by Sir Isaac Newton (one of the best)
360/(180-165)=24the 360 comes from the sum of the exterior angles proof and the 180 comes from the linear pair of exterior angles.
alternate exterior angles theorem
180
The degrees inside a triangle _always_ add up to 180. Do you need proof?
There is no proof - diagrammatical or otherwise - since it is not true. The sum of the internal angles of a hexagon, for example, is 720 degrees, while for a triangle the sum is 180 degrees - not half of 720.
Mathematical logic and proof theory (a branch of mathematical logic) for proof
180 Proof: 30-60-90 Triangle 45-45-90 * * * * * The answer is correct, but two examples (or even a million) do not constitute mathematical PROOF.
Because the 4 interior angles of any quadrilateral add up to 360 degrees and a cyclic quadrilateral diagonals opposite angles add up to 180 degrees therefore it follows that the other pair must be 180 degrees
Yes. All hexagons have interior angles totalling 720 degrees, whether they are regular or irregular. The proof of this is fairly easy.
No, there is no mathematical proof of God's existence. The existence of God is a matter of faith and belief, not something that can be proven through mathematical equations.
Absolutely. Depending on the triangles angle it shouldn't be more or less that 180°.
well accoring to my calculations the angle sum of a quadrilateral is equal to the sum of 360 degress the way u do this is u find the exterior angles of one side of a quuadrilateral and do it for all the other sides if you have any other questions please post it to a new site call www.freewebs.com/1pkc thankyou we are more than welcome to help u