How do you prove the following equation the quantity of sin theta divided by 1 minus cos theta minus the quantity 1 plus cos theta divided by sin theta equals 0?

Answer 1

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sin^2x + cos^2x = 1=> sin^2x = 1 - cos^x = (1 + cosx)(1 - cosx)

Divide both sides by sinx (assuming that sinx is not zero).

=> sinx = (1 + cosx)(1 - cosx)/sinx

Divide both sides by (1 - cosx)

=> sinx/(1 - cosx) = (1 + cosx)/sinx

=> sinx/(1 - cosx) - (1 + cosx)/sinx = 0