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What is x plus 2a?
x + 2a
What is The sum of fifty-two and a number?
Expressed algebraically, this is equal to 52 + x.
What is the sum of the first 11 terms of the arithmetic series in which a1 -12 and d 5?
Sum = n/2(2a + (n-1)d) = 11/2 x (2 x -12 + 10 x 5) = 11/2 x 26 = 143
What is 2 to the power of 0 why?
20 = 1Consider what is the value of 2a ÷ 2a? Any number divided by itself is 1. Thus:2a ÷ 2a = 1The law of indices says that when dividing, they are subtracted, for example:25 ÷ 22 = (2 x 2 x 2 x 2 x 2) ÷ (2 x 2) = 2 x 2 x 2 = 23 = 25-2So 2a ÷ 2a is (also):2a ÷ 2a = 2a-a = 20Since any number subtracted from itself is 0 (= a - a). This must have the same value as before, thus:20 = 1The 2 above can be replaced by any number x which means that any number to the power 0 is 1:x0 = 1
Find two numbers whose sum is sixty-five and such that one is four times as large as the other?
The answer is X-13 + Y- 52 = Sum 65
Sum of angles in a 52 sided shape?
180 x (52-2) = 9000 The sum of the interior angles is 9000 degrees.
If f of x equals 3x - 10 then what is f of 2a?
if f(x) = 3x - 10, then whatever is put (substituted) for x in the "f(x)" bit is substituted for x in the "3x - 10" bit. Thus f(2a) = 3(2a) - 10 = 6a - 10.
2a x 2a?
The answer is 4a^2.
What is x plus 2a?
x + 2a
What is the answer to 2a x 3b?
2a x 3b = 6ab
What is The sum of fifty-two and a number?
Expressed algebraically, this is equal to 52 + x.
What is 2a x a?
2a2
What is the sum of the first 11 terms of the arithmetic series in which a1 -12 and d 5?
Sum = n/2(2a + (n-1)d) = 11/2 x (2 x -12 + 10 x 5) = 11/2 x 26 = 143
What are three consecutive integers with the sum -153?
x + (x+1) + (x+2) = -153 3x + 3 = -153 3x = -156 x = -52 The three numbers are therefore: -52,-51 & -50.
What are the 4 consecutive even numbers that sum up to 220?
(x) + (x+2) + (x+4) + (x+6) = 220 4x + 12 = 220 4x = 208 x = 52 52, 54, 56, 58 Check: 52+54+56+58 = 220
What is the sum of 32 20 as the product of their GCF and another sum?
32 + 20 = 4 x (8 + 5)
What is the axis of symmetry formula?
-b/2a. i think.To show this, consider this equation:y = ax² + bx + cFactor out the a:y = a(x² + bx/a + c/a)Then, complete the squares to get:y = a(x² + bx/a + (b/(2a))² + c/a - (b/(2a))²)= a((x + (b/2a))² + c/a - (b/(2a))²)= a(x + (b/2a))² + c - b/(4a)By the vertex form:y = a(x - h)² + k where x = h is the axis of symmetry.So the general axis of symmetry for the quadratic equation is x = -b/(2a).
