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Sum = n/2(2a + (n-1)d)

= 11/2 x (2 x -12 + 10 x 5)

= 11/2 x 26

= 143

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What is the sum of the arithmetic series below?

To calculate the sum of an arithmetic series, you can use the formula ( S_n = \frac{n}{2} (a + l) ), where ( S_n ) is the sum, ( n ) is the number of terms, ( a ) is the first term, and ( l ) is the last term. If you provide the specific details of the series, I can help compute the sum directly.


What is meant by arithmetic sum?

That refers to the sum of an arithmetic series.


What is the sum of the first 28 terms of this arithmetic sequence?

To find the sum of the first 28 terms of an arithmetic sequence, you need the first term (a) and the common difference (d). The formula for the sum of the first n terms (S_n) of an arithmetic sequence is S_n = n/2 * (2a + (n - 1)d). Once you have the values of a and d, plug them into the formula along with n = 28 to calculate the sum.


What is the formula of arithmetic series?

The formula for the sum of an arithmetic series is given by ( S_n = \frac{n}{2} (a + l) ) or ( S_n = \frac{n}{2} (2a + (n - 1)d) ), where ( S_n ) is the sum of the first ( n ) terms, ( a ) is the first term, ( l ) is the last term, ( d ) is the common difference, and ( n ) is the number of terms. The first formula uses the first and last terms, while the second uses the first term and the common difference.


The answer to this question Find the sum of the first 25 elements what series -5 19 43 67?

-5 19 43 67 ...This is an arithmetic sequence because each term differs from the preceding term by a common difference, 24.In order to find the sum of the first 25 terms of the series constructed from the given arithmetic sequence, we need to use the formulaSn = [2t1 + (n - 1)d] (substitute -5 for t1, 25 for n, and 24 for d)S25 = [2(-5) + (25 - 1)24]S25 = -10 + 242S25 = 566Thus, the sum of the first 25 terms of an arithmetic series is 566.

Related Questions

What is an arithmetic series?

An arithmetic series is the sum of the terms in an arithmetic progression.


What is the sum of the arithmetic series below?

To calculate the sum of an arithmetic series, you can use the formula ( S_n = \frac{n}{2} (a + l) ), where ( S_n ) is the sum, ( n ) is the number of terms, ( a ) is the first term, and ( l ) is the last term. If you provide the specific details of the series, I can help compute the sum directly.


What is meant by arithmetic sum?

That refers to the sum of an arithmetic series.


The sum of the first 5 terms of an arithmetic series is 85. The sum of the first 6 terms is 123. Determine the first four terms of the series.?

Suppose the first term is a, the second is a+r and the nth is a+(n-1)r. Then the sum of the first five = 5a + 10r = 85 and the sum of the first six = 6a + 15r = 123 Solving these simultaneous equations, a = 3 and r = 7 So the first four terms are: 3, 10, 17 and 24


The sum of the first 5 terms of an arithmetic sequence is 40 and the sum of its first ten terms is 155what is this arithmetic sequence?

a1=2 d=3 an=a1+(n-1)d i.e. 2,5,8,11,14,17....


What is the formula of arithmetic series?

The formula for the sum of an arithmetic series is given by ( S_n = \frac{n}{2} (a + l) ) or ( S_n = \frac{n}{2} (2a + (n - 1)d) ), where ( S_n ) is the sum of the first ( n ) terms, ( a ) is the first term, ( l ) is the last term, ( d ) is the common difference, and ( n ) is the number of terms. The first formula uses the first and last terms, while the second uses the first term and the common difference.


Who gave the formula for finding sum of the first 'n' terms in Arithmetic Progression?

RAMANUJANRAMANUJAN


Find the sum of the first 48 terms of an aritmetic sequance 2 4 6 8?

To find the sum of the first 48 terms of an arithmetic sequence, we can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum of the first n terms, a1 is the first term, and an is the nth term. In this case, a1 = 2, n = 48, and an = 2 + (48-1)*2 = 96. Plugging these values into the formula, we get: S48 = 48/2 * (2 + 96) = 24 * 98 = 2352. Therefore, the sum of the first 48 terms of the given arithmetic sequence is 2352.


What is the sum of the first 15 terms of an arithmetic?

For an Arithmetic Progression, Sum = 15[a + 7d].{a = first term and d = common difference} For a Geometric Progression, Sum = a[1-r^15]/(r-1).{r = common ratio }.


What is the sum of the first ten terms of the arithmetic sequence 4 4.2 4.4...?

49


The answer to this question Find the sum of the first 25 elements what series -5 19 43 67?

-5 19 43 67 ...This is an arithmetic sequence because each term differs from the preceding term by a common difference, 24.In order to find the sum of the first 25 terms of the series constructed from the given arithmetic sequence, we need to use the formulaSn = [2t1 + (n - 1)d] (substitute -5 for t1, 25 for n, and 24 for d)S25 = [2(-5) + (25 - 1)24]S25 = -10 + 242S25 = 566Thus, the sum of the first 25 terms of an arithmetic series is 566.


What is the sum of all the numbers from 51 to 150?

To find the sum of all numbers from 51 to 150, we can use the formula for the sum of an arithmetic series: (n/2)(first term + last term), where n is the number of terms. In this case, the first term is 51, the last term is 150, and the number of terms is 150 - 51 + 1 = 100. Plugging these values into the formula, we get (100/2)(51 + 150) = 50 * 201 = 10,050. Therefore, the sum of all numbers from 51 to 150 is 10,050.