This is an expression, not an equation.
To rearrange it, you arrange the expression so that the first set of terms have a variable (letter) in common. Arrange the rest so that they follow a similar patter (see working below). Then factorise.
2pr + 6qs - 3qr - 4ps.
Select r to be the common variable for the first two terms.
So 2pr - 3qr + 6qs - 4ps
You will see that terms (now numbered) 3 and 4 have s in common. But, while with the first two, the term with p comes before the term with q, with 3 and 4, it is the other way around. So swap terms 3 and 4.
2pr - 3qr - 4ps + 6qs
Common factor of terms 1 and 2 = r, common factor of terms 3 and 4 = s:
r(2p - 3q) - 2s(2p - 3q)
and then (2p - 3q) is a common factor
so (2p - 3q)(r - 2s)
yes because every of mathematics is an equation
Solve for what? Do you want to rearrange the equation for y to be a function of x? y = 70 - 4x Do you want to rearrange it as a function of y? x = (70 - y) / 4 You'll need to be more specific in exactly what you want done.
To solve the equation (5p + 7p = 1ten + x), first combine like terms on the left side: (12p = 1ten + x). The term "1ten" seems unclear; if it refers to 10, then the equation simplifies to (12p = 10 + x). To isolate (x), rearrange it to (x = 12p - 10).
The letters 'y', 'm', 'x' plus 'b' in mathematics mean a specific number in an algebraic equation. The objective is to work out what the values of the letters are.
Rearrange the second equation as x = 10+y and then substitute it into the first equation which will create a quadratic equation in the form of: 2y2+30y+100 = 0 and when solved y = -10 or y = -5 Therefore the solutions are: x = 0, y = -10 and x = 5, y = -5
yes because every of mathematics is an equation
Assuming the question is about chemical reactions (rather than mathematics where it is placed), it is a double displacement.
Solve for what? Do you want to rearrange the equation for y to be a function of x? y = 70 - 4x Do you want to rearrange it as a function of y? x = (70 - y) / 4 You'll need to be more specific in exactly what you want done.
Rearrange the quadratic equation to: x2-6x-9 = 0 and use the quadratic equation formula to find the values of x which are:- x = -1.2426406871 or x = 7.2426406871 When factored: (x+1.2426406871)(x-7.242406871) = 0
There are 0, or no solutions to these equations. If you rearrange each equation to look like an equation of a line, you will have the two lines:y = x -1 and y = x + 1, which are two parallel lines. They do not intersect at any point, so there is no solution.
To solve the equation (5p + 7p = 1ten + x), first combine like terms on the left side: (12p = 1ten + x). The term "1ten" seems unclear; if it refers to 10, then the equation simplifies to (12p = 10 + x). To isolate (x), rearrange it to (x = 12p - 10).
The letters 'y', 'm', 'x' plus 'b' in mathematics mean a specific number in an algebraic equation. The objective is to work out what the values of the letters are.
Rearrange the second equation as x = 10+y and then substitute it into the first equation which will create a quadratic equation in the form of: 2y2+30y+100 = 0 and when solved y = -10 or y = -5 Therefore the solutions are: x = 0, y = -10 and x = 5, y = -5
1.1x2 + 3.3x + 4 = 6 First rearrange the equation to equal zero so that we can use the quadratic formula. 1.1x2 + 3.3x - 2 = 0 Using the quadratic formula, the solutions are x = -3.52 and x = 0.52 Both of these solutions are real, so the original equation has two real solutions.
The equation (9p + 8 = 10p + 7) is an open equation because it contains a variable, (p), and is not universally true or false for all values of (p). To determine if it can be true for some value of (p), we can rearrange it. Subtracting (9p) from both sides gives (8 = p + 7), which simplifies to (p = 1). Therefore, the equation is true when (p = 1), but false for other values of (p).
A quadratic equation.
Yes. 3a plus 12 plus 6 is an example of an Equation.