Rearrange the quadratic equation to: x2-6x-9 = 0 and use the quadratic equation formula to find the values of x which are:-
x = -1.2426406871 or x = 7.2426406871
When factored: (x+1.2426406871)(x-7.242406871) = 0
With great difficulty not knowing if 6x and 27 are plus or minus
-x(x2 - 2)(x2 + 3)
x2+6x-7 = (x+7)(x-1) when factored
x(6x - 11)
(x - 6)(x2 + 6x + 36)
(x - 3)(x - 2)
x2 + 6x + 8 = (x + 4)(x + 2)
The quadratic expression x2+6x+8 when factorised equals (x+2)(x+4)
Not factorable
x2 + 6x + 5 can be factored into (x+1) (x+5)
x2-6x+9 = (x-3)(x-3) when factorised.
x2 + 6x + 9 = 81 x2 + 6x = 72 x2 + 6x - 72 = 0 (x+12)(x-6) = 0 x= -12, 6 (two solutions)
6x3 - x2 + 17 = 2x2 + 47 6x3 - x2 - 2x2 = 47 - 17 x2(6x - 1 - 2) = 30 this is the simplest factorisation.
x2 + 6x + 12 = 0 x2 + 6x + 9 = -3 (x + 3)2 = -3 x + 3 = ± √-3 x = -3 ± i√3
(x + 3)(x + 3)
x2 + 6x + 8 =(x + 2)(x +4)
one