The number of bits required to represent an integer number depends on the size of the integer, there is no absolute answer. Generally speaking, a binary number made up of some number of bits can be considered to directly represent an integer number according to the rules of binary arithmetic. If you specify the question a little differently you can come up with a question that does have an absolute answer. For example, if you ask what range of integers can be represented by a binary number with N bits, the answer is exactly 0 to 2^N (ignoring alternate ways to characterize binary numbers such as signed two's complement). More specifically, an 8 bit binary number can represent the integers from 0 to 255. There is also another way to restate your original question. That would be to assume that you are asking how many bits (at a minimum) does it take to represent a particular integer. In that case, again assuming unsigned binary arithmetic, the answer would be found by determining the next higher power of two than the number in question and finding log base 2 of that number. For example, the minimum number of bits required to represent the integer 60 would be 6, where the next higher power of two than 60 is 64, and the log base 2 (simply the power to which 2 must be raised to arrive at the number) is 6. In theory, an infinite number of bits could represent an infinity of integers, but that is probably not really what you are asking.
50 is an integer.
The only two numbers that represent a binary digit are 0 and 1
it is itself in a binary form :) but if its in decimal form.. then its binary equivalent will be..(10011100011011) if it is in binry form.. its equivalent will be..(19)
5
jibibygyyug
The highest unsigned integer is 255; The highest signed integer is 127.
Binary bits are necessary to represent 748 different numbers in the sense that binary bits are represented in digital wave form. Binary bits also have an exponent of one.
It is the integer's expansion in binary.
111 The three ones represent (4)+(2)+(1).
binary integer don't think so... It's binary digit.
I am not!
The number of bits required to represent an integer number depends on the size of the integer, there is no absolute answer. Generally speaking, a binary number made up of some number of bits can be considered to directly represent an integer number according to the rules of binary arithmetic. If you specify the question a little differently you can come up with a question that does have an absolute answer. For example, if you ask what range of integers can be represented by a binary number with N bits, the answer is exactly 0 to 2^N (ignoring alternate ways to characterize binary numbers such as signed two's complement). More specifically, an 8 bit binary number can represent the integers from 0 to 255. There is also another way to restate your original question. That would be to assume that you are asking how many bits (at a minimum) does it take to represent a particular integer. In that case, again assuming unsigned binary arithmetic, the answer would be found by determining the next higher power of two than the number in question and finding log base 2 of that number. For example, the minimum number of bits required to represent the integer 60 would be 6, where the next higher power of two than 60 is 64, and the log base 2 (simply the power to which 2 must be raised to arrive at the number) is 6. In theory, an infinite number of bits could represent an infinity of integers, but that is probably not really what you are asking.
You could write it as a mixed number (12 and 4/4) but it wouldn't be in simplest form. The simplest form of any integer is the integer itself.
50 is an integer.
Binary Integer
The only two numbers that represent a binary digit are 0 and 1