0
To rewrite the equation of a parabola in standard form, you need to express it as ( y = a(x - h)^2 + k ) for a vertically oriented parabola or ( x = a(y - k)^2 + h ) for a horizontally oriented parabola. Here, ( (h, k) ) represents the vertex of the parabola, and ( a ) determines its direction and width. You can achieve this by completing the square on the quadratic expression.
What else can I help you with?
Is y(x 1)(x-3) an equation for this parabola?
To determine if ( y = (x - 1)(x - 3) ) is an equation for a parabola, we can rewrite it in standard form. Expanding this gives ( y = x^2 - 4x + 3 ), which is indeed a quadratic equation representing a parabola. Therefore, yes, ( y = (x - 1)(x - 3) ) is an equation for a parabola.
Rewrite y equals -6x plus 4 in standard form?
The equation of the line is written in the standard form, y = mx+c
Rewrite standard form equation into slope intercept equation y 6x-4?
10
How do you write an equation for a parabola in standard form?
To write an equation for a parabola in standard form, use the format ( y = a(x - h)^2 + k ) for a vertical parabola or ( x = a(y - k)^2 + h ) for a horizontal parabola. Here, ((h, k)) represents the vertex of the parabola, and (a) determines the direction and width of the parabola. If (a > 0), the parabola opens upwards (or to the right), while (a < 0) indicates it opens downwards (or to the left). To find the specific values of (h), (k), and (a), you may need to use given points or the vertex of the parabola.
What does the point h k represent in x ay - k2 h the standard form of equation for a parabola?
In the standard form of the equation of a parabola, (y = a(x - h)^2 + k) or (x = a(y - k)^2 + h), the point ( (h, k) ) represents the vertex of the parabola. This point is crucial as it indicates the location where the parabola changes direction, and it serves as the minimum or maximum point depending on the orientation of the parabola. The value of (a) determines the width and the direction (upward or downward) of the parabola.
Is y(x 1)(x-3) an equation for this parabola?
To determine if ( y = (x - 1)(x - 3) ) is an equation for a parabola, we can rewrite it in standard form. Expanding this gives ( y = x^2 - 4x + 3 ), which is indeed a quadratic equation representing a parabola. Therefore, yes, ( y = (x - 1)(x - 3) ) is an equation for a parabola.
What is the standard equation of the parabola y3(x-4)2-22?
the standard form of the equation of a parabola is x=y2+10y+22
What is the standard equation of a parabola?
There are two standard form of parabola: y2 = 4ax & x2 = 4ay, where a is a real number.
What is the standard form for a quadratic equation?
Normally a quadratic equation will graph out into a parabola. The standard form is f(x)=a(x-h)2+k
The vertex form of the equation of a parabola is y x-5 2 plus 16 what is the standard form of the equation?
In the equation y x-5 2 plus 16 the standard form of the equation is 13. You find the answer to this by finding the value of X.
Rewrite y equals -6x plus 4 in standard form?
The equation of the line is written in the standard form, y = mx+c
Rewrite standard form equation into slope intercept equation y 6x-4?
10
What is the standard form of the equation of a parabola that opens left or right?
x= ay² + by + c Apex :3
What different information do you get from vertex form and quadratic equation in standard form?
The graph of a quadratic function is always a parabola. If you put the equation (or function) into vertex form, you can read off the coordinates of the vertex, and you know the shape and orientation (up/down) of the parabola.
It is always helpful to rewrite an equation in standard form as a first step in solving it.?
True
What does the point h and k represent in the standard form of equation for a parabola?
It depends on where points h and k are, in which parabola. Since you have chosen not to share that information, there cannot be any sensible answer to this question.
What is the equation of the directrix of the parabola?
The answer depends on the form in which the equation of the parabola is given. For y^2 = 4ax the directrix is x = -2a.
