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The equation of the line is written in the standard form, y = mx+c
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The answer depends on the form in which the equation of the parabola is given. For y^2 = 4ax the directrix is x = -2a.
At any point on the y-axis, the x-coordinate is zero. In the equation of the parabola, set x=0. Tidy it up, and you have " Y = the y-intercept ".
Assuming the vertex is 0,0 and the directrix is y=4 x^2=0