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Determine whether the parabola y equals -x2 plus 15x plus 8 opens up down left or right?
when you have y=+/-x2 +whatever, the parabola opens up y=-(x2 +whatever), the parabola opens down x=+/-y2 +whatever, the parabola opens right x=-(y2 +whatever), the parabola opens left so, your answer is up
How do you get a parabola with only one x intercept?
To have a parabola with only one x-intercept, the vertex of the parabola must lie on the x-axis. This means the parabola opens either upwards or downwards, depending on the coefficient of the squared term in the equation. If the coefficient is positive, the parabola opens upwards, and if it is negative, the parabola opens downwards. By adjusting the coefficients in the equation of the parabola, you can position the vertex such that there is only one x-intercept.
What is the standard form of x2 10x y 200?
Let's say you want the standard form of the equation x2 + 10x + y + 20 = 0. x2 + 10x + y + 20 = 0 (add 5 and subtract y to both sides) x2 + 10x + 25 = -y + 5 (form the square to the left, and factor out -1 to the right) (x + 5)2 = -(y - 5) which is in the standard form (x - h)2 = 4p(y - k), where (h, k) = (-5, 5) is the vertex, and 4p = -1 yields p = -1/4, so the parabola opens downward.
Which equation describes a parabola that opens left or right and whose vertex is at the point h v?
your answer would actually be x=a(y-v)2+h
How do you find the solution of a quadratic equation graphically?
You write the equation in such a way that you have zero on the right side. Then you graph the expression on the left side of the equal sign, and check where it touches the x-axis. Note that this method works for most common equations.
Given the standard equation for a parabola opening left or right which way does a parabola open when the coefficient of the y2-term a is positive?
right
Given the standard equation for a parabola opening left or right which way does a parabola open when the coefficient of the y2-term a is positive Left or right?
left
Determine whether the parabola y equals -x2 plus 15x plus 8 opens up down left or right?
when you have y=+/-x2 +whatever, the parabola opens up y=-(x2 +whatever), the parabola opens down x=+/-y2 +whatever, the parabola opens right x=-(y2 +whatever), the parabola opens left so, your answer is up
What is a parabola that opens to the right called?
It is a square root mapping. This is not a function since it is a one-to-many mapping.
How do you get a parabola with only one x intercept?
To have a parabola with only one x-intercept, the vertex of the parabola must lie on the x-axis. This means the parabola opens either upwards or downwards, depending on the coefficient of the squared term in the equation. If the coefficient is positive, the parabola opens upwards, and if it is negative, the parabola opens downwards. By adjusting the coefficients in the equation of the parabola, you can position the vertex such that there is only one x-intercept.
What does 4 stands for in equation of parabola square of square of y equals 4ax?
A parabola with an equation, y2 = 4ax has its vertex at the origin and opens to the right. It's not just the '4' that is important, it's '4a' that matters. This type of parabola has a directrix at x = -a, and a focus at (a, 0). By writing the equation as it is, the position of the directrix and focus are readily identifiable. For example, y2 = 2.4x doesn't say a great deal. Re-writing the equation of the parabola as y2 = 4*(0.6)x tells us immediately that the directrix is at x = -0.6 and the focus is at (0.6, 0)
Which way does a parabola open when the coefficient of its y2term a is negative?
Nose points right, opens to the left.
In the standard equation for a hyperbola that opens left and right the value b equals half the length of the hyperbola's transverse axis?
True
How does the value of b affect the parabola?
The value of ( b ) in a quadratic equation of the form ( y = ax^2 + bx + c ) affects the position and shape of the parabola. Specifically, it influences the location of the vertex along the x-axis and the direction in which the parabola opens. A larger absolute value of ( b ) can make the parabola wider or narrower depending on the value of ( a ), while the sign of ( b ) can shift the vertex left or right. Overall, these changes alter how the parabola intersects with the x-axis and its symmetry.
How do you find the vertex of a parabola?
Solution 1Start by putting the parabola's equation into the form y = ax2 + bx + c if it opens up or down,or x = ay2 + by + c if it is opens to the left or right,where a, b, and c are constants.The x-value for the vertex is -(b/2a). You can use this x-value to solve for the y-value by substituting the x value in the original quadratic equation.Solution 2Put the parabola's equation into this form: y - k = 4p(x - h)2or x - h = 4p(y - k)2You just need to simplify the equation until it looks like this. The vertex is located at the coordinates (h,k). (p is for the focus, but that isn't important as long as you know h and k.)
What is the definition of parabola?
There are several ways of defining a parabola. Here are some:Given a straight line and a point not on that line, a parabola is the locus of all points that are equidistant from that point (the focus) and the line (directrix).A parabola is the intersection of the surface of a right circular cone and a plane parallel to a generating line of that surface.A parabola is the graph of a quadratic equation.
The equation below describes a parabola. If a is positive which way does the parabola open y ax2?
right apex. hope that helps
