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I am assuming that 2n is an algebraic expression, and n is limited to positive integer values. The first 4 multiples of 2n are 0 (2n*0), 2n (2n*1), 4n (2n*2), and 6n (2n*3). If you are looking for non-0 multiples, you would also include 8n (2n*4).
You can't. 17 + 2n = 21 + 2n gives: 2n = 4 + 2n which gives 0=4 which is not possible so the sum is not solveable.
It's an algbraic expession in the form of: 2n+4
2n/3 = 4 2n = 3*4 2n = 12 n = 6 :)
'n' can be any number, but when applied to (2n + 4), n = 2.5