3p9
The expression (2r \times 3p) involves multiplying two terms. To simplify, you multiply the coefficients (2 and 3) and the variables separately: (2 \times 3 = 6) and (r \times p = rp). Therefore, the result is (6rp).
It is y^3/x^2
(3^2)^3 is 3^()2x3=3^6
To simplify the expression (\frac{3^{-4} \cdot 2^3 \cdot 3^2}{2^4 \cdot 3^n}), first combine the powers of 3 in the numerator: (3^{-4 + 2} = 3^{-2}). The expression becomes (\frac{3^{-2} \cdot 2^3}{2^4 \cdot 3^n}). Next, simplify the powers of 2: (\frac{2^3}{2^4} = 2^{-1}). Thus, the simplified expression is (\frac{2^{-1} \cdot 3^{-2}}{3^n} = \frac{2^{-1}}{3^{n+2}}).
To simplify (6^2 \times 6^3), you can use the property of exponents that states (a^m \times a^n = a^{m+n}). In this case, you add the exponents: (2 + 3 = 5). Therefore, (6^2 \times 6^3 = 6^5).
The expression (2r \times 3p) involves multiplying two terms. To simplify, you multiply the coefficients (2 and 3) and the variables separately: (2 \times 3 = 6) and (r \times p = rp). Therefore, the result is (6rp).
Simpley, 2(to the power of)3 as there are 3 2's after the first :-)
It is y^3/x^2
(3^2)^3 is 3^()2x3=3^6
To simplify the expression -5p³(4p² + 3p¹), distribute -5p³ to both terms inside the parentheses. This results in -5p³ * 4p² = -20p^(3+2) = -20p⁵ and -5p³ * 3p¹ = -15p^(3+1) = -15p⁴. Therefore, the final expression is -20p⁵ - 15p⁴.
m7/2
27^(2/3) = [cuberoot(27)]^2 = 3^2 = 9
13 + 3p = -2subtract 13 from each side, 3p = -15divide each side by 3, p = -5
3+2+3²-1 = 5+8-1=12
Oh, what a happy little question! To simplify 3p over 5p, we can cancel out the p in the numerator and denominator, leaving us with 3 over 5. It's just like painting a beautiful landscape - sometimes we need to simplify our colors to create a harmonious picture.
(2^2)^3= 2^6 = 64 your welcome, look in your textbook. ;0
To simplify the expression (\frac{3^{-4} \cdot 2^3 \cdot 3^2}{2^4 \cdot 3^n}), first combine the powers of 3 in the numerator: (3^{-4 + 2} = 3^{-2}). The expression becomes (\frac{3^{-2} \cdot 2^3}{2^4 \cdot 3^n}). Next, simplify the powers of 2: (\frac{2^3}{2^4} = 2^{-1}). Thus, the simplified expression is (\frac{2^{-1} \cdot 3^{-2}}{3^n} = \frac{2^{-1}}{3^{n+2}}).