2x2-12x-54 = 0 Solve by factoring or using the quadratic equation formula or by completing the square: (2x+6)(x-9) = 0 Therefore: x = -3 or x = 9
2x2-10+7 = 0 Solving the quadratic equation using the quadratic formula will give you two solutions and they are: x = (5 - the square root of 11)/2 or x = (5 + the square root of 11)/2
2x2 = x2 - 2 Subtract x2 from both sides: x2 = -2 Take square roots: x = + or - i*sqrt(2) where i is the imaginary sqrt of -1.
2x2 = 228 divide both sides by 2 x2 = 114 x = ±√114 by the square root property
By using the quadratic equation formula: x = -5 and x = 3
2x2-12x-54 = 0 Solve by factoring or using the quadratic equation formula or by completing the square: (2x+6)(x-9) = 0 Therefore: x = -3 or x = 9
2x2-10+7 = 0 Solving the quadratic equation using the quadratic formula will give you two solutions and they are: x = (5 - the square root of 11)/2 or x = (5 + the square root of 11)/2
Without an equality sign and not knowing the plus or minus values of 3x and 3 the information given can't be considered to be a quadratic equation.
I'm sorry but I can't solve that problem. B(
2x2 = x2 - 2 Subtract x2 from both sides: x2 = -2 Take square roots: x = + or - i*sqrt(2) where i is the imaginary sqrt of -1.
2x2 = 228 divide both sides by 2 x2 = 114 x = ±√114 by the square root property
About 5.656854249 cm using Pythagoras' theorem: 2x2 = 64
By using the quadratic equation formula: x = -5 and x = 3
2x2+12x+1 = 0 By dividing all terms in the quadratic equation by 2 will make completing the square easier to work out: x2+6x+0.5 = 0 (x+3)2+0.5 = 0 (x+3)2-9+0.5 = 0 (x+3)2-8.5 = 0 (x+3)2 = 8.5 x+3 = the square root of 8.5 x = -3 and plus or minus the square root of 8.5
2x2
y = 2x2 - 3x - 1 = 0 After graphing this equation on my calculator, I found that there are in fact two answers, but neither of them are integers. This means that it is impossible to factor this quadratic equation in the form (x + a)(x + b) with a and b being integers.
216- 2x2