Best Answer

2x2 = 228 divide both sides by 2

x2 = 114

x = ±√114 by the square root property

Q: How do you solve 2x to the second power equals 228 by square root?

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If T2 = 78, then T = 78(1/2) or the square root of 78, or about 8.83.

5 ^x = 0 5 = root square 0 5=0

H= v over pie r to the second

87

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If T2 = 78, then T = 78(1/2) or the square root of 78, or about 8.83.

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You can solve for resistance using the formula ( R = \frac{V^2}{P} ), where R is the resistance, V is the voltage, and P is the power. By rearranging the formula, you can solve for resistance by dividing the square of the voltage by the power.

E is energy and MC2 is matter used to the second power... now you solve it

5 ^x = 0 5 = root square 0 5=0

-2y square exp power -2x-1

H= v over pie r to the second

87

If x equals the square root of ...., then you already have solved for x

It depends on which variable you wish to solve for.

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