To solve the equation (-5xy - 3 = 5x - 3y - 1), first rearrange it to isolate terms involving (x) and (y). Combine like terms to get (5x + 3y - 5xy = 2). Depending on the context, you can factor or simplify further, or solve for one variable in terms of the other. If you're looking for specific solutions, you may need additional information or constraints.
If you mean to say what the slope intercept form of 5x-3y=0 the that is y=5/3x
5x-19 = 16 5x = 16+19 5x = 35 x = 7
-5x+50 = 25 -5x = 25-50 -5x = -25 x = 5
5x + 2 = 22 5x = 22 - 2 5x = 20 5x/5 = 20/5 x=4
10x
If you mean to say what the slope intercept form of 5x-3y=0 the that is y=5/3x
(5x + y)(25x^2 - 5xy + y^2)
Lets start by putting the known number on the other side. Y3 -7500y=125000. There is your start. Take it from here.
5x-19 = 16 5x = 16+19 5x = 35 x = 7
-5x+50 = 25 -5x = 25-50 -5x = -25 x = 5
No, because it is not an equation (or inequality), but simply two expressions separated by a space.
128
5x + 2 = 22 5x = 22 - 2 5x = 20 5x/5 = 20/5 x=4
78
10x
To solve for ( y ) in the equation ( 5x = 2y^3 ), you first isolate ( y^3 ) by dividing both sides by 2: ( y^3 = \frac{5x}{2} ). Then, take the cube root of both sides to solve for ( y ): ( y = \sqrt[3]{\frac{5x}{2}} ).
5x - 1 = 24 5x - 1 + 1 = 24 + 1 5x = 25 5x/5 = 25/5 x = 5