3x - 5 = 2y3/2X - 5/2 = y
y=-10 sin 5x sin 5x=y/-10 x=asin(y/-10)/5
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It seems there might be a typographical error in your question, as "5x y 18" isn't a standard mathematical expression. If you're trying to solve for (x) or (y) in an equation that involves these variables, please provide the full equation (e.g., (5x + y = 18)). Once you have a complete equation, you can isolate one variable to solve for it.
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No.
3x - 5 = 2y3/2X - 5/2 = y
y=-10 sin 5x sin 5x=y/-10 x=asin(y/-10)/5
if you mean 5x -2y = 10 then y = 2.5x -5
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y = 5x^3 - 45x is a polynomial equation that crosses the y axis at x=3.
This cannot be solved. It needs 2 equations to solve for 2 unknowns.
y = 2x -1 y = 5x -13 So: 5x -13 = 2x -1 5x -2x = 13 -1 3x = 12 x = 4 and by substituting y = 7
0
That's not an equation, it is not solveable.
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