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14y minus 6y means "14 times a number, minus 6 times the same number". If you have 14 things and you take away 6 things, you are left with 8 things.

So, 8 times a number equals 48.

8 times what number gets you 48?

Since you are already in Algebra I, you know 8 times 6 gets you 48, so the number (y) is 6.

The formal Algebra I approach is to combine like terms, then divide.

14y - 6y = 48 (Subtract 6y from 14 y. (14y - 6y = 8y, and the y does not go away)

8y = 48 (Now divide both sides by 8 to get the y all by itself)

8/8y = 48/8 (8/8 is 1, and 48/8 is 6, so 1y = 6. You can lose the 1 because one thing is the thing itself.)

y = 6

Does that help? There are many ways to solve this problem, but Algebra I is teaching the proper steps for solving one, two and three step equations. Stick with it.

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13y ago
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Q: How do you solve 14y minus 6y equals 48 Alegebra 1?
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