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14y minus 6y means "14 times a number, minus 6 times the same number". If you have 14 things and you take away 6 things, you are left with 8 things.
So, 8 times a number equals 48.
8 times what number gets you 48?
Since you are already in Algebra I, you know 8 times 6 gets you 48, so the number (y) is 6.
The formal Algebra I approach is to combine like terms, then divide.
14y - 6y = 48 (Subtract 6y from 14 y. (14y - 6y = 8y, and the y does not go away)
8y = 48 (Now divide both sides by 8 to get the y all by itself)
8/8y = 48/8 (8/8 is 1, and 48/8 is 6, so 1y = 6. You can lose the 1 because one thing is the thing itself.)
y = 6
Does that help? There are many ways to solve this problem, but Algebra I is teaching the proper steps for solving one, two and three step equations. Stick with it.
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What is the value of y if 14y equals 98?
If: 14y = 98 Then: y = 7
What is 2y-7 equals 14y plus 29 Y equals?
2y-7 = 14y+29 2y = 14y + 36 -12y = 36 -y = 3 y = -3
Solve by substitution x plus 5y equal 10 and 7x minus 14y equal 49?
set it up as x+5y=10 and 7x-14y=49 on top of each other and then multiply x+5y=10 by -7. That gives you -7x-35y=-70. cross out the X's and add the Y's. -21y=21 divide and get -1=y then sub. for x and solve. X=15 and X=5
What is the solution set for the equation y2 plus 14y equals 0?
(0, -14)
What is 5y-14y?
5y - 14y = -9y
