(0, -14)
2y-7 = 14y+29 2y = 14y + 36 -12y = 36 -y = 3 y = -3
If: 14y = 98 Then: y = 7
The center of the circle is at (9, 7) on the Cartesian plane
6x+14y+8x-18y = 14x-4y
14y - 51 = 187 + 4ySubtract 4y from each side:10y - 51 = 187Add 51 to each side:10y = 238Divide each side by 10:y = 23.8
It is not possible to solve a single linear equation in two variables.
2y-7 = 14y+29 2y = 14y + 36 -12y = 36 -y = 3 y = -3
x = -2 and y = 0
It equals 3 more than (14 times y)
The equation 7 x + 14 y + 10 z = 98001 has infinite solutions. For any x and y we can have a z which satisfies this equation. For example, if we choose x=1 and y=1 then z=9798 satisfies. To have a specific solution there must be three equations for three unknowns (x,y,z), which can be solved simultaneously.
If: 14y = 98 Then: y = 7
The center of the circle is at (9, 7) on the Cartesian plane
6x+14y+8x-18y = 14x-4y
If: 6+17y = 15+14y then 17y-14y = 15-6 so 3y = 9 and then y = 3
Equation: x^2 + y^2 +10x -14y +10 = 0 Completing the squares: (x+5)^2 + (y-7) -25-49 +10 = 0 So: (x+5)^2 + (y-7) = 64 Therfore the circle's centre is at (-5, 7) and its radius is 8
Without an equality sign and not knowing the plus or minus values of some of the given terms it can't be considered to be an equation.
Multiply both sides by 2y. 1/2y = 7 1 = 14y y = 1/14