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Q: How do i solve this 5x2 + 3x2 – x3 + 2x3 + 10x4 – 5x4?

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There is no single coefficient for that equation, as a coefficient is the number by which any term is multiplied. The coefficients in that equation are 5, 2, 4 and 3.

5x2-18x+9 = (5x-3)(x-3)

It is 5x2 - 20

The answer is 37.

x3 + 5x2 - x - 5 = (x2 - 1)(x + 5) = (x + 1)(x - 1)(x + 5)

Related questions

10x3 + 3x2

3x2 - 5x2 = -2x2

In algebra and mathematics the simple above equation can be written and simplified as follows . (5x2 8x)-(3x2-x) = 10 + 8x -6 +x = 4 +7x.

2x3 - 7 + 5x - x3 + 3x - x3 = 8x - 7

5x2 + 3x2 = 16

its 10

5x2-8x-4

Use iterative adds. 5x2= 5+5 10x4= 10+10+10+10

algebra: 5[2x3(22-13)+3] mathematical: 5x2

All six of them

3x4-7x3+5x2-3x+6

because of WACC nature, there are no same utility, and that's why none make same calculation. so WACC=X2+2X3+5X2=0 ? because of WACC nature, there are no same utility, and that's why none make same calculation. so WACC=X2+2X3+5X2=0 ?

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