x2 • (5x2 + x + 8)
There is no single coefficient for that equation, as a coefficient is the number by which any term is multiplied. The coefficients in that equation are 5, 2, 4 and 3.
5x2-18x+9 = (5x-3)(x-3)
Are you asking how to solve for x if those two expressions equal each other? -3x2 - 5x + 1 = 8x2 - 2x - 9 11x2 + 3x - 10 = 0 11x2 + 3x = 10 x2 + 3x/11 = 10/11 x2 + 3x/11 + (3/22)2 = 10/11 + (3/22)2 (x + 3/22)2 = 440/484 + 9/484 x + 3/22 = ± √(449 / 484) x = 3/22 ± √449 / 22 x = (3 ± √449) / 22 Are you asking to find the derivatives of each expression? if f(x) = -3x2 - 5x + 1 f'(x) = -6x - 5 if f(x) = 8x2 - 2x - 9 f'(x) = 16x - 2 Are you looking for their indefinite integrals? ∫(-3x2 - 5x + 1)dx = -x3 - 5x2/2 + x + C ∫(8x2 - 2x - 9)dx = 8x3/3 - x2 - 9x + C
It is 5x2 - 20
You convert the mixed number to an improper fraction ie. 1 and 2/3 converts to 5/3Then find a common denominator ie. 5/3 and 1/2 could have a common denominator of /6Next you find out how much you times the denominators by to get the /6 and use that number to times the numerators ie. 3x2=6 so 5x2=10 10/6 and 2x3=6 1x3=3 3/6Now add these two together as you would normally ie.3/6+10/6= 13/6Finally you convert it back to a mixed number ie. 13/6 converts to 2 and 1/6!Hope this helps!
10x3 + 3x2
In algebra and mathematics the simple above equation can be written and simplified as follows . (5x2 8x)-(3x2-x) = 10 + 8x -6 +x = 4 +7x.
3x2 - 5x2 = -2x2
2x3 - 7 + 5x - x3 + 3x - x3 = 8x - 7
5x2 + 3x2 = 16
Use iterative adds. 5x2= 5+5 10x4= 10+10+10+10
algebra: 5[2x3(22-13)+3] mathematical: 5x2
5x2-8x-4
All six of them
its 10
because of WACC nature, there are no same utility, and that's why none make same calculation. so WACC=X2+2X3+5X2=0 ? because of WACC nature, there are no same utility, and that's why none make same calculation. so WACC=X2+2X3+5X2=0 ?
3x4-7x3+5x2-3x+6