You look for two integers which multiply to 33 and whose sum is 14 and these happen to be 11 and 3. So x^2 - 14x + 33 = x^2 - 3x - 11x + 33 =(x^2 - 3x) - (11x - 33) [sign for 33 changes because the bracket has a minus sign] =x * (x-3) + 11 * (x-3) =(x - 3) * (x - 11)
33y =11x +49 y= 11/33 X +49/33 The slope is coefficient of x. Y = mx+c. m is the slope here. So the slope of above equation is 1/3 --> 0.33
x=10 100x-89x=110 11x=110 x=10
If you set your equation to equal 7, then you can move 7 to the other side of the equation, and solve for x. This/these values will always result in 7. e.g. 3x2+11x+6=7 3x2+11x+6-7=7-7 3x2+11x-1=0 Factor using the quadratic formula and solve for x.
11x - 8 = 8 + 1 Simplify the right hand side: 11x - 8 = 9 Add 8 to both sides: 11x = 17 Divide both sides by 11: x = 17/11 or 16/11
-11x-27=-49 11x+27=49 11x=22 x=2
1) x=21 2) x=14.45
-10x = x-33 -10x-x = -33 -11x = -33 x = 11
11 x 2= 22 x+x=2 22 divided by 2= 11 22+11= 33 33-5=28
To solve for x: x2 = 11x - 10 x2 - 11x = -10 x2 - 11x + 10 =0 (x - 1)(x - 10) = 0 x = {1, 10)
12x = 11x - 5, subtract both sides by 11x x = -5
If 6x + 10 = 11x , then x=2.
11x = 10x-19 Subtact 10x fromboth sides:- x = -19
9132
-7
12x - 5 = 11x + 5(1) add 5 to both sides:12x - 5 + 5 = 11x + 5 + 512x = 11x + 10(2) next subtract 11x from both sides:12x - 11x = 11x - 11x + 10x = 10
x=12