your equation is this... 2x3 + 11x = 6x 2x3 + 5x = 0 x(2x2 + 5) = 0 x = 0 and (5/2)i and -(5/2)i
-8x + 5 - 3x = -6Combine the 'x' terms on the left side:-11x + 5 = -6Subtract 5 from each side:-11x = -11Divide each side by -11:x = 1
Substitute 2x - 6 for y in first equation: 12x - 5(2x - 6) = 30 ie 12x - 10x + 30 = 30 so 2x = 0 making x = 0 and y = -6
7
12x - 5 = 30Add 5 to each side:12x = 35Divide each side by 12:x = 35/12=======================y = 2x - 6Substitute the value of 'x' :y = 2(35/12) - 6Clear parentheses:y = 35/6 - 6y = 35/6 - 36/6y = -1/6
12x - 5 = 11x + 5(1) add 5 to both sides:12x - 5 + 5 = 11x + 5 + 512x = 11x + 10(2) next subtract 11x from both sides:12x - 11x = 11x - 11x + 10x = 10
17
Write as an equation with division before subtraction. 5/11x-7=2 5/11x=9 mult both sides by 11x 5=99x 99x=5 x=5/99
If: y = 4x^2 -12x -3 and y = x^2 +11x +5 Then: 4x^2 -12x -3 = x^2 +11x +5 Transposing terms: 3x^2 -23x -8 = 0 Factorizing: (3x+1)(x-8) = 0 => x = -1/3 or x = 8 Therefore the x coordinates are: -1/3 and 8
When x = 5, 12x = 12*5 = 60.
12x + 17 = 7 Subtract 17 from both sides: 12x = -10 Divide both sides by 12: x = -10/12 = -5/6
6y = 12x+32 Divide all terms by 6: y = 2x+5 and 1/3 which is now in slope intercept form
5/4x+7/12x is the same as 15/12x+7/12x = 21/12x
13x + 15 = 11x - 5 2x = -20 x = -10
x=55/-11=-5
x2+12x+5 = 3 x2+12x+5-3 = 0 x2+12x+2 = 0
A: 11x = 5y + 80 B: 9x - 15y = 120 A: 11x - 5y = 80 B: 9x - 15y = 120 A: 11x - 5y = 80 B: 3x - 5y = 40 A - B: 8x = 40 x = 5 Now we can plug that value of x into one of the original equations to solve for y: 11(5) - 5y = 80 55 - 5y = 80 -5y = 25 y = -5