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12x = 11x - 5, subtract both sides by 11x

x = -5

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Q: How do you solve 12x equals 11x - 5?
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How do you solve 12 x - 5 equals 11 x plus 5?

12x - 5 = 11x + 5(1) add 5 to both sides:12x - 5 + 5 = 11x + 5 + 512x = 11x + 10(2) next subtract 11x from both sides:12x - 11x = 11x - 11x + 10x = 10


Y equals -x plus 12x-y equals 5 solve by substitution?

17


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If: y = 4x^2 -12x -3 and y = x^2 +11x +5 Then: 4x^2 -12x -3 = x^2 +11x +5 Transposing terms: 3x^2 -23x -8 = 0 Factorizing: (3x+1)(x-8) = 0 => x = -1/3 or x = 8 Therefore the x coordinates are: -1/3 and 8


How do you solve this problem 12x when x 5?

When x = 5, 12x = 12*5 = 60.


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What is x if 13x plus 15 equals 11x-5?

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What is the answer to -11x equals 55?

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What is the elimination method for 11x equals 5y plus 80 and 9x-15y equals 120?

A: 11x = 5y + 80 B: 9x - 15y = 120 A: 11x - 5y = 80 B: 9x - 15y = 120 A: 11x - 5y = 80 B: 3x - 5y = 40 A - B: 8x = 40 x = 5 Now we can plug that value of x into one of the original equations to solve for y: 11(5) - 5y = 80 55 - 5y = 80 -5y = 25 y = -5