30-2=28 so 2x=28 28 divided by 2=14, so x is 14
This equation is unsolvable without knowing one of the values of either x or y.
-8x + 4y = 28 Add 8x to each side: 4y = 8x + 28 Divide both sides by 4: y = 2x + 7
28 + 28 = 56.56 + 28 = 84.
22+22+28+28=100.
Set up the equation and solve for z: 28 + z = 56 (next, subtract 28 from each side of the equaition to solve) z = 28
a2+30a+56=0 , solve for a Using the quadratic formula, you will find that: a=-2 , a=-28
28
n = 28
There's nothing to solve. If it equaled something, you could solve it. For example, if x^2 - 28 = 0, then x = the square root of 28, which simplifies to plus or minus 2 times the square root of 7.
30-2=28 so 2x=28 28 divided by 2=14, so x is 14
This equation is unsolvable without knowing one of the values of either x or y.
-8x + 4y = 28 Add 8x to each side: 4y = 8x + 28 Divide both sides by 4: y = 2x + 7
28 + 28 = 56.56 + 28 = 84.
22+22+28+28=100.
28
4m = 28 m = 7 You first put all the "m"s on one side so it becomes 4m = 28 You then divide 28 by 4 and you get 7 I'm not completely sure if it's right