0
4 sin2x = 1.
Then,
(2sinx)2 = 1,
2sinx = ±1, and
sinx = ±½.
Whence,
x = 90° or 270°;
or, in radians,
x = π/2 or 3π/2.
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How do you solve 2 sin squared x plus sin x equals 1?
2 sin2 x + sin x = 1. Letting s = sin x, we have: 2s2 + s - 1 = (2s - 1)(s + 1) = 0; whence, sin x = ½ or -1, and x = 30° or 150° or 270°. Or, if you prefer, x = π/6 or 5π/6 or 3π/2.
How do you solve a squared plus a plus ab plus b equals 0?
That factors to (a + 1)(a + b) a = -1, -b b = -a
Is 1- cos 2 x 1 plus cos 2 x equals sin squared x cos squared x an identity?
No, (sinx)^2 + (cosx)^2=1 is though
X squared plus y squared minus 1 all cubed then minus the product of x squared times y cubed that all equals 0 How do you solve for y?
You have to put your heart into it!
Can the number 1 be squared?
Yes and the answer is 1 squared equals 1
How do you solve 2 sin squared theta equals one fourth?
2 sin^2 theta = 1/4 sin^2 theta = 1/8 sin theta = sqrt(1/8) theta = arcsin(sqrt(1/8))
If cos and theta 0.65 what is the value of sin and theta?
You can use the Pythagorean identity to solve this:(sin theta) squared + (cos theta) squared = 1.
What is Sin squared x - Cos squared x divided by 1 - Tan squared x equals cos squared x?
22
If Sin equals x and Cos equals y then x squared equals what function of y?
If x = sin θ and y = cos θ then: sin² θ + cos² θ = 1 → x² + y² = 1 → x² = 1 - y²
What does cos squared x - Sin squared x equal?
2 x cosine squared x -1 which also equals cos (2x)
How do you solve 2 sin squared x plus sin x equals 1?
2 sin2 x + sin x = 1. Letting s = sin x, we have: 2s2 + s - 1 = (2s - 1)(s + 1) = 0; whence, sin x = ½ or -1, and x = 30° or 150° or 270°. Or, if you prefer, x = π/6 or 5π/6 or 3π/2.
What is sin squared equal to?
Sin squared is equal to 1 - cos squared.
How do you prove that the sin over one minus the cosine minus one plus the cosine over the sine equals zero?
Multiply both sides by sin(1-cos) and you lose the denominators and get (sin squared) minus 1+cos times 1-cos. Then multiply out (i.e. expand) 1+cos times 1-cos, which will of course give the difference of two squares: 1 - (cos squared). (because the cross terms cancel out.) (This is diff of 2 squares because 1 is the square of 1.) And so you get (sin squared) - (1 - (cos squared)) = (sin squared) + (cos squared) - 1. Then from basic trig we know that (sin squared) + (cos squared) = 1, so this is 0.
Can you solve x squared minus six plus five equals zero?
X=1
How do you solve sin x multiplied to Sin squared x is equal to 1?
sin(x)*sin2(x) = 1 so sin3(x) = 1 so that sin(x) = cuberoot(1) = 1 then x = pi/2 + n*pi where n is an integer.
What is 1 minus cos squared?
sin squared
Is 1- cos 2 x 1 plus cos 2 x equals sin squared x cos squared x an identity?
No, (sinx)^2 + (cosx)^2=1 is though
