4 sin2x = 1.
Then,
(2sinx)2 = 1,
2sinx = ±1, and
sinx = ±½.
Whence,
x = 90° or 270°;
or, in radians,
x = π/2 or 3π/2.
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2 sin2 x + sin x = 1. Letting s = sin x, we have: 2s2 + s - 1 = (2s - 1)(s + 1) = 0; whence, sin x = ½ or -1, and x = 30° or 150° or 270°. Or, if you prefer, x = π/6 or 5π/6 or 3π/2.
No, (sinx)^2 + (cosx)^2=1 is though
That factors to (a + 1)(a + b) a = -1, -b b = -a
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The answer is 1. sin^2 x cos^2/sin^2 x 1/cos^2 cos^2 will be cancelled =1 sin^2 also will be cancelled=1 1/1 = 1