2t^2 - 98 = 0
add 98 to each side
2t^2 = 98
divide both sides by 2
t^2 = 49
take square root of both sides
t = +/- sqrt(49)
t = +/- 7
you should see that this checks
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If x squared -10 = 0 then x = the square root of 10
Solve using the quadratic formula
3x2-9x = 0 x(3x-9) = 0 x = 0 or x = 3
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x = 25 / 3squared + 5